Input interpretation
copper aluminum oxide | molar mass
Result
Find the molar mass, M, for copper aluminum oxide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CuAl_2O_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Al (aluminum) | 2 Cu (copper) | 1 O (oxygen) | 4 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Al (aluminum) | 2 | 26.9815385 Cu (copper) | 1 | 63.546 O (oxygen) | 4 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Al (aluminum) | 2 | 26.9815385 | 2 × 26.9815385 = 53.9630770 Cu (copper) | 1 | 63.546 | 1 × 63.546 = 63.546 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M = 53.9630770 g/mol + 63.546 g/mol + 63.996 g/mol = 181.505 g/mol
Unit conversion
0.18151 kg/mol (kilograms per mole)
Comparisons
≈ 0.25 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.93 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms) | 182 u (unified atomic mass units) | 182 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 182