Input interpretation
![vanadyl dichloride | molar mass](../image_source/44673e36b01ff568a19fd9c01b7c2222.png)
vanadyl dichloride | molar mass
Result
![Find the molar mass, M, for vanadyl dichloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: VOCl_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 O (oxygen) | 1 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 O (oxygen) | 1 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 70.90 g/mol + 15.999 g/mol + 50.9415 g/mol = 137.84 g/mol](../image_source/c908687e2287ae7660e8dcb7565a465e.png)
Find the molar mass, M, for vanadyl dichloride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: VOCl_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Cl (chlorine) | 2 O (oxygen) | 1 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Cl (chlorine) | 2 | 35.45 O (oxygen) | 1 | 15.999 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Cl (chlorine) | 2 | 35.45 | 2 × 35.45 = 70.90 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 70.90 g/mol + 15.999 g/mol + 50.9415 g/mol = 137.84 g/mol
Unit conversion
![0.1378 kg/mol (kilograms per mole)](../image_source/0244ae9c17b2d887e47fb67f8a179906.png)
0.1378 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/78895757fe1db822b7e3bf0ddf648f45.png)
≈ ( 0.19 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.71 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/6faf27e42cdb15784d9dc370afbafbff.png)
≈ 0.71 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/afb618ccb67f280020187d4e0d8fec0d.png)
≈ 2.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 138 u (unified atomic mass units) | 138 Da (daltons)](../image_source/8ac340d1a4262d2f2285a5919a3c3f23.png)
Mass of a molecule m from m = M/N_A: | 2.3×10^-22 grams | 2.3×10^-25 kg (kilograms) | 138 u (unified atomic mass units) | 138 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 138](../image_source/10120427d59066b7557e2de40a2566a2.png)
Relative molecular mass M_r from M_r = M_u/M: | 138