Input interpretation
![3-chlorophenylzinc iodide | molar mass](../image_source/ed746f7ca53ead2405b692a1207cc613.png)
3-chlorophenylzinc iodide | molar mass
Result
![Find the molar mass, M, for 3-chlorophenylzinc iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ClC_6H_4ZnI Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 Cl (chlorine) | 1 H (hydrogen) | 4 I (iodine) | 1 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 4 | 1.008 I (iodine) | 1 | 126.90447 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 72.066 g/mol + 35.45 g/mol + 4.032 g/mol + 126.90447 g/mol + 65.38 g/mol = 303.83 g/mol](../image_source/41d9b269dfa9af86dc88364030f5353f.png)
Find the molar mass, M, for 3-chlorophenylzinc iodide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ClC_6H_4ZnI Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 Cl (chlorine) | 1 H (hydrogen) | 4 I (iodine) | 1 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 4 | 1.008 I (iodine) | 1 | 126.90447 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 4 | 1.008 | 4 × 1.008 = 4.032 I (iodine) | 1 | 126.90447 | 1 × 126.90447 = 126.90447 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 72.066 g/mol + 35.45 g/mol + 4.032 g/mol + 126.90447 g/mol + 65.38 g/mol = 303.83 g/mol
Unit conversion
![0.3038 kg/mol (kilograms per mole)](../image_source/a0a8856d4ac1e52c5a10671a7dff27e2.png)
0.3038 kg/mol (kilograms per mole)
Comparisons
![≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/49088ca7ae74b75846f0054715f8e59c.png)
≈ 0.42 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/7144fe1c5e653e4a8e4a2cbdb8a3e7c4.png)
≈ 1.6 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/479e0e850f4a44a9f9e52cce220276ff.png)
≈ 5.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 304 u (unified atomic mass units) | 304 Da (daltons)](../image_source/2870a27ac16130ed52e00fdf27a528ca.png)
Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 304 u (unified atomic mass units) | 304 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 304](../image_source/2ee17cf74e61de0b05facce0fc7c2fe2.png)
Relative molecular mass M_r from M_r = M_u/M: | 304