Input interpretation
hydrogen iodide + bromic acid ⟶ water + iodine + hydrogen bromide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, I, Br and O: H: | c_1 + c_2 = 2 c_3 + c_5 I: | c_1 = 2 c_4 Br: | c_2 = c_5 O: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 3 c_4 = 3 c_5 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 + ⟶ 3 + 3 +
Structures
+ ⟶ + +
Names
hydrogen iodide + bromic acid ⟶ water + iodine + hydrogen bromide
Chemical names and formulas
| hydrogen iodide | bromic acid | water | iodine | hydrogen bromide Hill formula | HI | BrHO_3 | H_2O | I_2 | BrH name | hydrogen iodide | bromic acid | water | iodine | hydrogen bromide IUPAC name | hydrogen iodide | bromic acid | water | molecular iodine | hydrogen bromide