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HNO3 + CaCO3 = H2CO3 + Ca(NO3)2

Input interpretation

HNO_3 nitric acid + CaCO_3 calcium carbonate ⟶ H_2CO_3 carbonic acid + Ca(NO_3)_2 calcium nitrate
HNO_3 nitric acid + CaCO_3 calcium carbonate ⟶ H_2CO_3 carbonic acid + Ca(NO_3)_2 calcium nitrate

Balanced equation

Balance the chemical equation algebraically: HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 CaCO_3 ⟶ c_3 H_2CO_3 + c_4 Ca(NO_3)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, C and Ca: H: | c_1 = 2 c_3 N: | c_1 = 2 c_4 O: | 3 c_1 + 3 c_2 = 3 c_3 + 6 c_4 C: | c_2 = c_3 Ca: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2
Balance the chemical equation algebraically: HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 CaCO_3 ⟶ c_3 H_2CO_3 + c_4 Ca(NO_3)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, C and Ca: H: | c_1 = 2 c_3 N: | c_1 = 2 c_4 O: | 3 c_1 + 3 c_2 = 3 c_3 + 6 c_4 C: | c_2 = c_3 Ca: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2

Structures

 + ⟶ +
+ ⟶ +

Names

nitric acid + calcium carbonate ⟶ carbonic acid + calcium nitrate
nitric acid + calcium carbonate ⟶ carbonic acid + calcium nitrate

Equilibrium constant

Construct the equilibrium constant, K, expression for: HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 CaCO_3 | 1 | -1 H_2CO_3 | 1 | 1 Ca(NO_3)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HNO_3 | 2 | -2 | ([HNO3])^(-2) CaCO_3 | 1 | -1 | ([CaCO3])^(-1) H_2CO_3 | 1 | 1 | [H2CO3] Ca(NO_3)_2 | 1 | 1 | [Ca(NO3)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([HNO3])^(-2) ([CaCO3])^(-1) [H2CO3] [Ca(NO3)2] = ([H2CO3] [Ca(NO3)2])/(([HNO3])^2 [CaCO3])
Construct the equilibrium constant, K, expression for: HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 CaCO_3 | 1 | -1 H_2CO_3 | 1 | 1 Ca(NO_3)_2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HNO_3 | 2 | -2 | ([HNO3])^(-2) CaCO_3 | 1 | -1 | ([CaCO3])^(-1) H_2CO_3 | 1 | 1 | [H2CO3] Ca(NO_3)_2 | 1 | 1 | [Ca(NO3)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HNO3])^(-2) ([CaCO3])^(-1) [H2CO3] [Ca(NO3)2] = ([H2CO3] [Ca(NO3)2])/(([HNO3])^2 [CaCO3])

Rate of reaction

Construct the rate of reaction expression for: HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 CaCO_3 | 1 | -1 H_2CO_3 | 1 | 1 Ca(NO_3)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HNO_3 | 2 | -2 | -1/2 (Δ[HNO3])/(Δt) CaCO_3 | 1 | -1 | -(Δ[CaCO3])/(Δt) H_2CO_3 | 1 | 1 | (Δ[H2CO3])/(Δt) Ca(NO_3)_2 | 1 | 1 | (Δ[Ca(NO3)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[HNO3])/(Δt) = -(Δ[CaCO3])/(Δt) = (Δ[H2CO3])/(Δt) = (Δ[Ca(NO3)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HNO_3 + CaCO_3 ⟶ H_2CO_3 + Ca(NO_3)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 CaCO_3 | 1 | -1 H_2CO_3 | 1 | 1 Ca(NO_3)_2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HNO_3 | 2 | -2 | -1/2 (Δ[HNO3])/(Δt) CaCO_3 | 1 | -1 | -(Δ[CaCO3])/(Δt) H_2CO_3 | 1 | 1 | (Δ[H2CO3])/(Δt) Ca(NO_3)_2 | 1 | 1 | (Δ[Ca(NO3)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HNO3])/(Δt) = -(Δ[CaCO3])/(Δt) = (Δ[H2CO3])/(Δt) = (Δ[Ca(NO3)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | nitric acid | calcium carbonate | carbonic acid | calcium nitrate formula | HNO_3 | CaCO_3 | H_2CO_3 | Ca(NO_3)_2 Hill formula | HNO_3 | CCaO_3 | CH_2O_3 | CaN_2O_6 name | nitric acid | calcium carbonate | carbonic acid | calcium nitrate IUPAC name | nitric acid | calcium carbonate | carbonic acid | calcium dinitrate
| nitric acid | calcium carbonate | carbonic acid | calcium nitrate formula | HNO_3 | CaCO_3 | H_2CO_3 | Ca(NO_3)_2 Hill formula | HNO_3 | CCaO_3 | CH_2O_3 | CaN_2O_6 name | nitric acid | calcium carbonate | carbonic acid | calcium nitrate IUPAC name | nitric acid | calcium carbonate | carbonic acid | calcium dinitrate

Substance properties

 | nitric acid | calcium carbonate | carbonic acid | calcium nitrate molar mass | 63.012 g/mol | 100.09 g/mol | 62.024 g/mol | 164.09 g/mol phase | liquid (at STP) | solid (at STP) | | solid (at STP) melting point | -41.6 °C | 1340 °C | | 562 °C boiling point | 83 °C | | |  density | 1.5129 g/cm^3 | 2.71 g/cm^3 | | 2.5 g/cm^3 solubility in water | miscible | insoluble | | soluble dynamic viscosity | 7.6×10^-4 Pa s (at 25 °C) | | |
| nitric acid | calcium carbonate | carbonic acid | calcium nitrate molar mass | 63.012 g/mol | 100.09 g/mol | 62.024 g/mol | 164.09 g/mol phase | liquid (at STP) | solid (at STP) | | solid (at STP) melting point | -41.6 °C | 1340 °C | | 562 °C boiling point | 83 °C | | | density | 1.5129 g/cm^3 | 2.71 g/cm^3 | | 2.5 g/cm^3 solubility in water | miscible | insoluble | | soluble dynamic viscosity | 7.6×10^-4 Pa s (at 25 °C) | | |

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