Search

H2 + Al + C2H2 = (C2H5)3Al

Input interpretation

H_2 hydrogen + Al aluminum + C_2H_2 acetylene ⟶ (C2H5)3Al
H_2 hydrogen + Al aluminum + C_2H_2 acetylene ⟶ (C2H5)3Al

Balanced equation

Balance the chemical equation algebraically: H_2 + Al + C_2H_2 ⟶ (C2H5)3Al Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 Al + c_3 C_2H_2 ⟶ c_4 (C2H5)3Al Set the number of atoms in the reactants equal to the number of atoms in the products for H, Al and C: H: | 2 c_1 + 2 c_3 = 15 c_4 Al: | c_2 = c_4 C: | 2 c_3 = 6 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9/2 c_2 = 1 c_3 = 3 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 9 c_2 = 2 c_3 = 6 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 H_2 + 2 Al + 6 C_2H_2 ⟶ 2 (C2H5)3Al
Balance the chemical equation algebraically: H_2 + Al + C_2H_2 ⟶ (C2H5)3Al Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 Al + c_3 C_2H_2 ⟶ c_4 (C2H5)3Al Set the number of atoms in the reactants equal to the number of atoms in the products for H, Al and C: H: | 2 c_1 + 2 c_3 = 15 c_4 Al: | c_2 = c_4 C: | 2 c_3 = 6 c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9/2 c_2 = 1 c_3 = 3 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 9 c_2 = 2 c_3 = 6 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 H_2 + 2 Al + 6 C_2H_2 ⟶ 2 (C2H5)3Al

Structures

+ + ⟶ (C2H5)3Al
+ + ⟶ (C2H5)3Al

Names

hydrogen + aluminum + acetylene ⟶ (C2H5)3Al
hydrogen + aluminum + acetylene ⟶ (C2H5)3Al

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2 + Al + C_2H_2 ⟶ (C2H5)3Al Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 9 H_2 + 2 Al + 6 C_2H_2 ⟶ 2 (C2H5)3Al Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 9 | -9 Al | 2 | -2 C_2H_2 | 6 | -6 (C2H5)3Al | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 9 | -9 | ([H2])^(-9) Al | 2 | -2 | ([Al])^(-2) C_2H_2 | 6 | -6 | ([C2H2])^(-6) (C2H5)3Al | 2 | 2 | ([(C2H5)3Al])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-9) ([Al])^(-2) ([C2H2])^(-6) ([(C2H5)3Al])^2 = ([(C2H5)3Al])^2/(([H2])^9 ([Al])^2 ([C2H2])^6)
Construct the equilibrium constant, K, expression for: H_2 + Al + C_2H_2 ⟶ (C2H5)3Al Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 9 H_2 + 2 Al + 6 C_2H_2 ⟶ 2 (C2H5)3Al Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 9 | -9 Al | 2 | -2 C_2H_2 | 6 | -6 (C2H5)3Al | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 9 | -9 | ([H2])^(-9) Al | 2 | -2 | ([Al])^(-2) C_2H_2 | 6 | -6 | ([C2H2])^(-6) (C2H5)3Al | 2 | 2 | ([(C2H5)3Al])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-9) ([Al])^(-2) ([C2H2])^(-6) ([(C2H5)3Al])^2 = ([(C2H5)3Al])^2/(([H2])^9 ([Al])^2 ([C2H2])^6)

Rate of reaction

Construct the rate of reaction expression for: H_2 + Al + C_2H_2 ⟶ (C2H5)3Al Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 9 H_2 + 2 Al + 6 C_2H_2 ⟶ 2 (C2H5)3Al Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 9 | -9 Al | 2 | -2 C_2H_2 | 6 | -6 (C2H5)3Al | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 9 | -9 | -1/9 (Δ[H2])/(Δt) Al | 2 | -2 | -1/2 (Δ[Al])/(Δt) C_2H_2 | 6 | -6 | -1/6 (Δ[C2H2])/(Δt) (C2H5)3Al | 2 | 2 | 1/2 (Δ[(C2H5)3Al])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/9 (Δ[H2])/(Δt) = -1/2 (Δ[Al])/(Δt) = -1/6 (Δ[C2H2])/(Δt) = 1/2 (Δ[(C2H5)3Al])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2 + Al + C_2H_2 ⟶ (C2H5)3Al Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 9 H_2 + 2 Al + 6 C_2H_2 ⟶ 2 (C2H5)3Al Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 9 | -9 Al | 2 | -2 C_2H_2 | 6 | -6 (C2H5)3Al | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 9 | -9 | -1/9 (Δ[H2])/(Δt) Al | 2 | -2 | -1/2 (Δ[Al])/(Δt) C_2H_2 | 6 | -6 | -1/6 (Δ[C2H2])/(Δt) (C2H5)3Al | 2 | 2 | 1/2 (Δ[(C2H5)3Al])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/9 (Δ[H2])/(Δt) = -1/2 (Δ[Al])/(Δt) = -1/6 (Δ[C2H2])/(Δt) = 1/2 (Δ[(C2H5)3Al])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| hydrogen | aluminum | acetylene | (C2H5)3Al formula | H_2 | Al | C_2H_2 | (C2H5)3Al Hill formula | H_2 | Al | C_2H_2 | C6H15Al name | hydrogen | aluminum | acetylene | IUPAC name | molecular hydrogen | aluminum | acetylene |
| hydrogen | aluminum | acetylene | (C2H5)3Al formula | H_2 | Al | C_2H_2 | (C2H5)3Al Hill formula | H_2 | Al | C_2H_2 | C6H15Al name | hydrogen | aluminum | acetylene | IUPAC name | molecular hydrogen | aluminum | acetylene |

Substance properties

| hydrogen | aluminum | acetylene | (C2H5)3Al molar mass | 2.016 g/mol | 26.9815385 g/mol | 26.038 g/mol | 114.17 g/mol phase | gas (at STP) | solid (at STP) | gas (at STP) | melting point | -259.2 °C | 660.4 °C | -81 °C | boiling point | -252.8 °C | 2460 °C | -75 °C | density | 8.99×10^-5 g/cm^3 (at 0 °C) | 2.7 g/cm^3 | 0.618 g/cm^3 (at -55 °C) | solubility in water | | insoluble | | surface tension | | 0.817 N/m | 0.01431 N/m | dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | 1.5×10^-4 Pa s (at 760 °C) | | odor | odorless | odorless | |
| hydrogen | aluminum | acetylene | (C2H5)3Al molar mass | 2.016 g/mol | 26.9815385 g/mol | 26.038 g/mol | 114.17 g/mol phase | gas (at STP) | solid (at STP) | gas (at STP) | melting point | -259.2 °C | 660.4 °C | -81 °C | boiling point | -252.8 °C | 2460 °C | -75 °C | density | 8.99×10^-5 g/cm^3 (at 0 °C) | 2.7 g/cm^3 | 0.618 g/cm^3 (at -55 °C) | solubility in water | | insoluble | | surface tension | | 0.817 N/m | 0.01431 N/m | dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | 1.5×10^-4 Pa s (at 760 °C) | | odor | odorless | odorless | |

Units

Random Queries

conductivity cesium
InChI identifier of terbium(III) oxide
iron(II) oxide
molar mass of phosphorus heptasulfide vs bismuth basic dichromate
hybridization of benzene
CAS number of lead(II) chlorite vs europium(III) phosphate hydrate
formula of platinum(IV) cation vs nickel(I) cation
chemical types 1-bromo-3-methyl-2-butene
name of shafranovskite
formula of acetic acid vs nitric acid