Input interpretation
ethoxide anion | structure diagram
Result
Draw the Lewis structure of ethoxide anion. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms, including the net charge: 2 n_C, val + 5 n_H, val + n_O, val - n_charge = 20 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): 2 n_C, full + 5 n_H, full + n_O, full = 34 Subtracting these two numbers shows that 34 - 20 = 14 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 7 bonds and hence 14 bonding electrons in the diagram. Fill in the remaining unbonded electrons on each atom. In total, there remain 20 - 14 = 6 electrons left to draw. Lastly, fill in the formal charges: Answer: | |