Input interpretation
HNO_3 nitric acid + Ba barium ⟶ H_2O water + NH_3 ammonia + Ba(NO_3)_2 barium nitrate
Balanced equation
Balance the chemical equation algebraically: HNO_3 + Ba ⟶ H_2O + NH_3 + Ba(NO_3)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 Ba ⟶ c_3 H_2O + c_4 NH_3 + c_5 Ba(NO_3)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and Ba: H: | c_1 = 2 c_3 + 3 c_4 N: | c_1 = c_4 + 2 c_5 O: | 3 c_1 = c_3 + 6 c_5 Ba: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 9 c_2 = 4 c_3 = 3 c_4 = 1 c_5 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 9 HNO_3 + 4 Ba ⟶ 3 H_2O + NH_3 + 4 Ba(NO_3)_2
Structures
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