Search

molar mass of 3-bromo-2-(3'-bromobenzyloxy)-5-methylphenylboronic acid

Input interpretation

3-bromo-2-(3'-bromobenzyloxy)-5-methylphenylboronic acid | molar mass
3-bromo-2-(3'-bromobenzyloxy)-5-methylphenylboronic acid | molar mass

Result

Find the molar mass, M, for 3-bromo-2-(3'-bromobenzyloxy)-5-methylphenylboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_13BBr_2O_3 Use the chemical formula, C_14H_13BBr_2O_3, to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 2  C (carbon) | 14  B (boron) | 1  O (oxygen) | 3  H (hydrogen) | 13 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Br (bromine) | 2 | 79.904  C (carbon) | 14 | 12.011  B (boron) | 1 | 10.81  O (oxygen) | 3 | 15.999  H (hydrogen) | 13 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808  C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154  B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  H (hydrogen) | 13 | 1.008 | 13 × 1.008 = 13.104  M = 159.808 g/mol + 168.154 g/mol + 10.81 g/mol + 47.997 g/mol + 13.104 g/mol = 399.87 g/mol
Find the molar mass, M, for 3-bromo-2-(3'-bromobenzyloxy)-5-methylphenylboronic acid: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_14H_13BBr_2O_3 Use the chemical formula, C_14H_13BBr_2O_3, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 2 C (carbon) | 14 B (boron) | 1 O (oxygen) | 3 H (hydrogen) | 13 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 2 | 79.904 C (carbon) | 14 | 12.011 B (boron) | 1 | 10.81 O (oxygen) | 3 | 15.999 H (hydrogen) | 13 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 2 | 79.904 | 2 × 79.904 = 159.808 C (carbon) | 14 | 12.011 | 14 × 12.011 = 168.154 B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 H (hydrogen) | 13 | 1.008 | 13 × 1.008 = 13.104 M = 159.808 g/mol + 168.154 g/mol + 10.81 g/mol + 47.997 g/mol + 13.104 g/mol = 399.87 g/mol

Unit conversion

0.3999 kg/mol (kilograms per mole)
0.3999 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.55 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.55 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.1 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 6.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 6.8 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.6×10^-22 grams  | 6.6×10^-25 kg (kilograms)  | 400 u (unified atomic mass units)  | 400 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.6×10^-22 grams | 6.6×10^-25 kg (kilograms) | 400 u (unified atomic mass units) | 400 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 400
Relative molecular mass M_r from M_r = M_u/M: | 400