Input interpretation
tributyltin bromide | molar mass
Result
![Find the molar mass, M, for tributyltin bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: [CH_3(CH_2)_3]_3SnBr Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 12 H (hydrogen) | 27 Sn (tin) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 12 | 12.011 H (hydrogen) | 27 | 1.008 Sn (tin) | 1 | 118.710 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 27 | 1.008 | 27 × 1.008 = 27.216 Sn (tin) | 1 | 118.710 | 1 × 118.710 = 118.710 M = 79.904 g/mol + 144.132 g/mol + 27.216 g/mol + 118.710 g/mol = 369.962 g/mol](../image_source/17fdd33f8a37ced3070f939fbe77e837.png)
Find the molar mass, M, for tributyltin bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: [CH_3(CH_2)_3]_3SnBr Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 12 H (hydrogen) | 27 Sn (tin) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 12 | 12.011 H (hydrogen) | 27 | 1.008 Sn (tin) | 1 | 118.710 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 27 | 1.008 | 27 × 1.008 = 27.216 Sn (tin) | 1 | 118.710 | 1 × 118.710 = 118.710 M = 79.904 g/mol + 144.132 g/mol + 27.216 g/mol + 118.710 g/mol = 369.962 g/mol
Unit conversion
0.36996 kg/mol (kilograms per mole)
Comparisons
≈ 0.51 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6.1×10^-22 grams | 6.1×10^-25 kg (kilograms) | 370 u (unified atomic mass units) | 370 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 370