Input interpretation
10, 16-dihydroxypalmitate | relative molecular mass
Result
Find the relative molecular mass, M_r, for 10, 16-dihydroxypalmitate: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_16H_32O_4 Use the chemical formula, C_16H_32O_4, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 16 H (hydrogen) | 31 O (oxygen) | 4 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u C (carbon) | 16 | 12.011 H (hydrogen) | 31 | 1.008 O (oxygen) | 4 | 15.999 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass C (carbon) | 16 | 12.011 | 16 × 12.011 = 192.176 H (hydrogen) | 31 | 1.008 | 31 × 1.008 = 31.248 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 M_r = 192.176 + 31.248 + 63.996 = 287.420
Comparisons
≈ 0.4 × relative molecular mass of fullerene ( ≈ 721 )
≈ 1.5 × relative molecular mass of caffeine ( ≈ 194 )
≈ 4.9 × relative molecular mass of sodium chloride ( ≈ 58 )
Corresponding quantities
Molar mass M from M = M_uM_r: | 287 g/mol (grams per mole)
Molecular mass m from m = M_rM_u/N_A: | 4.8×10^-22 grams | 4.8×10^-25 kg (kilograms)