Input interpretation
aluminum + fluorine ⟶ aluminum fluoride
Balanced equation
Balance the chemical equation algebraically: + ⟶ Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Al and F: Al: | c_1 = c_3 F: | 2 c_2 = 3 c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 3/2 c_3 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 2 c_2 = 3 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + 3 ⟶ 2
Structures
+ ⟶
Names
aluminum + fluorine ⟶ aluminum fluoride
Reaction thermodynamics
Enthalpy
| aluminum | fluorine | aluminum fluoride molecular enthalpy | 0 kJ/mol | 0 kJ/mol | -1510 kJ/mol total enthalpy | 0 kJ/mol | 0 kJ/mol | -3021 kJ/mol | H_initial = 0 kJ/mol | | H_final = -3021 kJ/mol ΔH_rxn^0 | -3021 kJ/mol - 0 kJ/mol = -3021 kJ/mol (exothermic) | |
Chemical names and formulas
| aluminum | fluorine | aluminum fluoride Hill formula | Al | F_2 | AlF_3 name | aluminum | fluorine | aluminum fluoride IUPAC name | aluminum | molecular fluorine | trifluoroalumane
Substance properties
| aluminum | fluorine | aluminum fluoride molar mass | 26.9815385 g/mol | 37.996806326 g/mol | 83.976748 g/mol phase | solid (at STP) | gas (at STP) | solid (at STP) melting point | 660.4 °C | -219.6 °C | 1040 °C boiling point | 2460 °C | -188.12 °C | density | 2.7 g/cm^3 | 0.001696 g/cm^3 (at 0 °C) | 3.1 g/cm^3 solubility in water | insoluble | reacts | surface tension | 0.817 N/m | | dynamic viscosity | 1.5×10^-4 Pa s (at 760 °C) | 2.344×10^-5 Pa s (at 25 °C) | odor | odorless | |
Units
