Input interpretation
![2-bromo-4, 6-difluorophenol | molar mass](../image_source/746fd9c655324ee3e5ae142e84e7da28.png)
2-bromo-4, 6-difluorophenol | molar mass
Result
![Find the molar mass, M, for 2-bromo-4, 6-difluorophenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_3BrF_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 6 F (fluorine) | 2 H (hydrogen) | 3 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 6 | 12.011 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 3 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 79.904 g/mol + 72.066 g/mol + 37.996806326 g/mol + 3.024 g/mol + 15.999 g/mol = 208.990 g/mol](../image_source/6c0fca9de69eab5abbd95397c2c3252c.png)
Find the molar mass, M, for 2-bromo-4, 6-difluorophenol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_3BrF_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 6 F (fluorine) | 2 H (hydrogen) | 3 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 6 | 12.011 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 3 | 1.008 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 3 | 1.008 | 3 × 1.008 = 3.024 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 79.904 g/mol + 72.066 g/mol + 37.996806326 g/mol + 3.024 g/mol + 15.999 g/mol = 208.990 g/mol
Unit conversion
![0.20899 kg/mol (kilograms per mole)](../image_source/b8c5b7e4a4e191ff71f392fa85152406.png)
0.20899 kg/mol (kilograms per mole)
Comparisons
![≈ 0.29 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/6dd517a178c6ca30fd8d6a6e3736de92.png)
≈ 0.29 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/3a0dc41419e0f7a47680babb34a121dc.png)
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 3.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/0277df489fd36dc670af93d856b07e5e.png)
≈ 3.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 3.5×10^-22 grams | 3.5×10^-25 kg (kilograms) | 209 u (unified atomic mass units) | 209 Da (daltons)](../image_source/33edde1d62b24577503957b180da5ced.png)
Mass of a molecule m from m = M/N_A: | 3.5×10^-22 grams | 3.5×10^-25 kg (kilograms) | 209 u (unified atomic mass units) | 209 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 209](../image_source/9968e8d09ed8cb1fc2c188cac45ed050.png)
Relative molecular mass M_r from M_r = M_u/M: | 209