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volume of 12 kg of potassium

Input interpretation

convert 12 kg of potassium (chemical element) to volume
convert 12 kg of potassium (chemical element) to volume

Results

14 L (liters)
14 L (liters)

Possible intermediate steps

Convert from kilograms into liters: 12 kg of K (potassium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 0.856 g/cm^3 (grams per cubic centimeter) at STP of K: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(0.856 g) = 14000 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (14000 cm^3)/1 × (1 mL)/(1 cm^3) = 14000 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: |   | (14000 mL)/1 × (1 L)/(1000 mL) = 14 L
Convert from kilograms into liters: 12 kg of K (potassium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 0.856 g/cm^3 (grams per cubic centimeter) at STP of K: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(0.856 g) = 14000 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (14000 cm^3)/1 × (1 mL)/(1 cm^3) = 14000 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: | | (14000 mL)/1 × (1 L)/(1000 mL) = 14 L

Unit conversions

0.014 m^3 (cubic meters)
0.014 m^3 (cubic meters)
14000 cm^3 (cubic centimeters)
14000 cm^3 (cubic centimeters)
29.6 pints
29.6 pints
14.8 quarts
14.8 quarts
3.7 gallons
3.7 gallons
0.495 ft^3 (cubic feet)
0.495 ft^3 (cubic feet)
855 in^3 (cubic inches)
855 in^3 (cubic inches)

Comparisons as volume

 ≈ ( 0.006 ≈ 1/150 ) × volume of paint needed to cover the outside surface of the White House ( ≈ 600 gal )
≈ ( 0.006 ≈ 1/150 ) × volume of paint needed to cover the outside surface of the White House ( ≈ 600 gal )
 ≈ 0.63 × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ 0.63 × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
 ≈ 2.5 × volume of a soccer ball ( 5310 to 5792 cm^3 )
≈ 2.5 × volume of a soccer ball ( 5310 to 5792 cm^3 )

Comparisons as volume of food or beverage

 ≈ 4.5 × volume of a US size 10 can ( 105 fl oz )
≈ 4.5 × volume of a US size 10 can ( 105 fl oz )
 ≈ 8.5 × volume of a US size 5 can ( 7 cups )
≈ 8.5 × volume of a US size 5 can ( 7 cups )
 ≈ 270 × volume of a standard US large egg ( 3.5 tbsp )
≈ 270 × volume of a standard US large egg ( 3.5 tbsp )

Interpretations

volume
volume
volume of food or beverage
volume of food or beverage
section modulus
section modulus

Basic unit dimensions

[length]^3
[length]^3

Corresponding quantities

Radius r of a sphere from V = 4πr^3/3:  | 15 cm (centimeters)  | 0.49 feet  | 5.9 inches
Radius r of a sphere from V = 4πr^3/3: | 15 cm (centimeters) | 0.49 feet | 5.9 inches
Edge length a of a cube from V = a^3:  | 24 cm (centimeters)  | 0.79 feet  | 9.5 inches
Edge length a of a cube from V = a^3: | 24 cm (centimeters) | 0.79 feet | 9.5 inches
Mass m of water from m = ρ_(H_2O)V:  | 14 kg (kilograms)  | 31 lb (pounds)  | (assuming maximum water density ≈ 1000 kg/m^3)
Mass m of water from m = ρ_(H_2O)V: | 14 kg (kilograms) | 31 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O):  | 4.686×10^26 molecules  | (assuming maximum water density ≈ 1000 kg/m^3)  | (assuming molecular mass of water ≈ 18.02 u)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 4.686×10^26 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)