Input interpretation
![thallium(I) nitrite | molar mass](../image_source/9842fb407cb9f06f193e6176ebae128e.png)
thallium(I) nitrite | molar mass
Result
![Find the molar mass, M, for thallium(I) nitrite: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: TlNO_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i N (nitrogen) | 1 O (oxygen) | 2 Tl (thallium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Tl (thallium) | 1 | 204.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 Tl (thallium) | 1 | 204.38 | 1 × 204.38 = 204.38 M = 14.007 g/mol + 31.998 g/mol + 204.38 g/mol = 250.39 g/mol](../image_source/7f90fb2ce0879dbfaf8f3506b4597997.png)
Find the molar mass, M, for thallium(I) nitrite: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: TlNO_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i N (nitrogen) | 1 O (oxygen) | 2 Tl (thallium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Tl (thallium) | 1 | 204.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 Tl (thallium) | 1 | 204.38 | 1 × 204.38 = 204.38 M = 14.007 g/mol + 31.998 g/mol + 204.38 g/mol = 250.39 g/mol
Unit conversion
![0.25038 kg/mol (kilograms per mole)](../image_source/ad7e015b0542b6019a84cdcca2668166.png)
0.25038 kg/mol (kilograms per mole)
Comparisons
![≈ 0.35 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/e38bed572bc387afe16e84e10c5d649f.png)
≈ 0.35 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/19e647f40ff13a89729b1da122f09726.png)
≈ 1.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.3 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/a0605cabe8d51baf8d87363dfc84aadc.png)
≈ 4.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.2×10^-22 grams | 4.2×10^-25 kg (kilograms) | 250 u (unified atomic mass units) | 250 Da (daltons)](../image_source/daf1e1dc8ac917348bfa2b691b3f91bc.png)
Mass of a molecule m from m = M/N_A: | 4.2×10^-22 grams | 4.2×10^-25 kg (kilograms) | 250 u (unified atomic mass units) | 250 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 250](../image_source/2223d959684f7f2c47a1bc6c13197886.png)
Relative molecular mass M_r from M_r = M_u/M: | 250