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molar mass of 4-O-acetyl-3,6-di-O-(tert-butyldimethylsilyl)-D-glucal

Input interpretation

4-O-acetyl-3, 6-di-O-(tert-butyldimethylsilyl)-D-glucal | molar mass
4-O-acetyl-3, 6-di-O-(tert-butyldimethylsilyl)-D-glucal | molar mass

Result

Find the molar mass, M, for 4-O-acetyl-3, 6-di-O-(tert-butyldimethylsilyl)-D-glucal: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_40O_5Si_2 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 20  H (hydrogen) | 40  O (oxygen) | 5  Si (silicon) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 20 | 12.011  H (hydrogen) | 40 | 1.008  O (oxygen) | 5 | 15.999  Si (silicon) | 2 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220  H (hydrogen) | 40 | 1.008 | 40 × 1.008 = 40.320  O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995  Si (silicon) | 2 | 28.085 | 2 × 28.085 = 56.170  M = 240.220 g/mol + 40.320 g/mol + 79.995 g/mol + 56.170 g/mol = 416.705 g/mol
Find the molar mass, M, for 4-O-acetyl-3, 6-di-O-(tert-butyldimethylsilyl)-D-glucal: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_40O_5Si_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 20 H (hydrogen) | 40 O (oxygen) | 5 Si (silicon) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 20 | 12.011 H (hydrogen) | 40 | 1.008 O (oxygen) | 5 | 15.999 Si (silicon) | 2 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220 H (hydrogen) | 40 | 1.008 | 40 × 1.008 = 40.320 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 Si (silicon) | 2 | 28.085 | 2 × 28.085 = 56.170 M = 240.220 g/mol + 40.320 g/mol + 79.995 g/mol + 56.170 g/mol = 416.705 g/mol

Unit conversion

0.4167 kg/mol (kilograms per mole)
0.4167 kg/mol (kilograms per mole)

Comparisons

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≈ 0.58 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.1 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 7.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 7.1 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 6.9×10^-22 grams  | 6.9×10^-25 kg (kilograms)  | 417 u (unified atomic mass units)  | 417 Da (daltons)
Mass of a molecule m from m = M/N_A: | 6.9×10^-22 grams | 6.9×10^-25 kg (kilograms) | 417 u (unified atomic mass units) | 417 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 417
Relative molecular mass M_r from M_r = M_u/M: | 417