Input interpretation
![N-phenylacrylamide | molar mass](../image_source/17852b21cb1840d6e7663ae1f428e2e6.png)
N-phenylacrylamide | molar mass
Result
![Find the molar mass, M, for N-phenylacrylamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5NHC(O)CH=CH_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 108.099 g/mol + 9.072 g/mol + 14.007 g/mol + 15.999 g/mol = 147.177 g/mol](../image_source/b64b8ed5b7765a648b527e5e6c8a0cf5.png)
Find the molar mass, M, for N-phenylacrylamide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5NHC(O)CH=CH_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 M = 108.099 g/mol + 9.072 g/mol + 14.007 g/mol + 15.999 g/mol = 147.177 g/mol
Unit conversion
![0.14718 kg/mol (kilograms per mole)](../image_source/e04db16b2a58aa01e642225281f9571f.png)
0.14718 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/e7d4d7ce8f89b656310fbecafacadb7c.png)
≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.76 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/79fdd544330147e092f297053bf68e6e.png)
≈ 0.76 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/628e9b959d080d82e853d100f6374ed1.png)
≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 147 u (unified atomic mass units) | 147 Da (daltons)](../image_source/fa134877b26f6fb928e87edf880644dd.png)
Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 147 u (unified atomic mass units) | 147 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 147](../image_source/ab05f606b169e3b6f21d2e9a3421265a.png)
Relative molecular mass M_r from M_r = M_u/M: | 147