Input interpretation
N-boc-trans-4-N-fmoc-amino-L-proline | molar mass
Result
Find the molar mass, M, for N-boc-trans-4-N-fmoc-amino-L-proline: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_25H_28N_2O_6 Use the chemical formula, C_25H_28N_2O_6, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 25 H (hydrogen) | 28 N (nitrogen) | 2 O (oxygen) | 6 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 25 | 12.011 H (hydrogen) | 28 | 1.008 N (nitrogen) | 2 | 14.007 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 25 | 12.011 | 25 × 12.011 = 300.275 H (hydrogen) | 28 | 1.008 | 28 × 1.008 = 28.224 N (nitrogen) | 2 | 14.007 | 2 × 14.007 = 28.014 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M = 300.275 g/mol + 28.224 g/mol + 28.014 g/mol + 95.994 g/mol = 452.507 g/mol
Unit conversion
0.45251 kg/mol (kilograms per mole)
Comparisons
≈ 0.63 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 7.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 7.5×10^-22 grams | 7.5×10^-25 kg (kilograms) | 453 u (unified atomic mass units) | 453 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 453