Input interpretation
convert 12 kg of protactinium (chemical element) to volume
Results
780.74 mL (milliliters)
Possible intermediate steps
Convert from kilograms into milliliters: 12 kg of Pa (protactinium) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 15.37 g/cm^3 (grams per cubic centimeter) at STP of Pa: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(15.37 g) = 780.74 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): Answer: | | (780.74 cm^3)/1 × (1 mL)/(1 cm^3) = 780.74 mL
Unit conversions
7.8074 dL (deciliters)
0.78074 L (liters)
780.74 cm^3 (cubic centimeters)
7.8074×10^-4 m^3 (cubic meters)
3.3 cups
26.4 fl oz (fluid ounces)
1.65 pints
0.825 quarts
0.20625 gallons
Comparisons as volume
≈ ( 0.035 ≈ 1/29 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ volume of a typical human breath ( ≈ 0.5 L )
≈ 12 × volume of an Apple iPhone 4 ( ≈ 6.3×10^-5 m^3 )
Comparisons as volume of food or beverage
≈ 0.83 × volume of a US size 3 can ( 4 cups )
≈ 0.94 × volume of a US size 2.5 can ( 3.5 cups )
≈ 1.4 × volume of a US size 2 can ( 19 fl oz )
Interpretations
volume
volume of food or beverage
section modulus
Basic unit dimensions
![[length]^3](../image_source/9a1040ed0a4bdd613748e162d1e8512e.png)
[length]^3
Corresponding quantities
Radius r of a sphere from V = 4πr^3/3: | 57 mm (millimeters) | 0.19 feet | 2.2 inches
Edge length a of a cube from V = a^3: | 92 mm (millimeters) | 0.3 feet | 3.6 inches
Mass m of water from m = ρ_(H_2O)V: | 781 grams | 1.7 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 2.61×10^25 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)