Input interpretation
![chlorodifluoromethane | molar mass](../image_source/34bd15d9adaf6444688f76737e2c2e97.png)
chlorodifluoromethane | molar mass
Result
![Find the molar mass, M, for chlorodifluoromethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CHClF_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 Cl (chlorine) | 1 F (fluorine) | 2 H (hydrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 1 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 M = 12.011 g/mol + 35.45 g/mol + 37.996806326 g/mol + 1.008 g/mol = 86.47 g/mol](../image_source/882587fa75b23144d298bbe86e4bb239.png)
Find the molar mass, M, for chlorodifluoromethane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CHClF_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 1 Cl (chlorine) | 1 F (fluorine) | 2 H (hydrogen) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 1 | 12.011 Cl (chlorine) | 1 | 35.45 F (fluorine) | 2 | 18.998403163 H (hydrogen) | 1 | 1.008 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 1 | 12.011 | 1 × 12.011 = 12.011 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 F (fluorine) | 2 | 18.998403163 | 2 × 18.998403163 = 37.996806326 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 M = 12.011 g/mol + 35.45 g/mol + 37.996806326 g/mol + 1.008 g/mol = 86.47 g/mol
Unit conversion
![0.08647 kg/mol (kilograms per mole)](../image_source/e1a6f085c476dff864814bd24b68f4f2.png)
0.08647 kg/mol (kilograms per mole)
Comparisons
![≈ ( 0.12 ≈ 1/8 ) × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/57546ae4b1d085a54bdfbb9e98d954ca.png)
≈ ( 0.12 ≈ 1/8 ) × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 0.45 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/3dfdf0253bf19f57dbc1cf2e9f0c9b85.png)
≈ 0.45 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 1.5 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/4ac27c07e2766bcda296b198bc84eeb3.png)
≈ 1.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 1.4×10^-22 grams | 1.4×10^-25 kg (kilograms) | 86 u (unified atomic mass units) | 86 Da (daltons)](../image_source/1f0f8d49e529bc0c78e2ea0fbdfe8ea3.png)
Mass of a molecule m from m = M/N_A: | 1.4×10^-22 grams | 1.4×10^-25 kg (kilograms) | 86 u (unified atomic mass units) | 86 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 86](../image_source/a340e701a355c316f4f7151d863a13ed.png)
Relative molecular mass M_r from M_r = M_u/M: | 86