Input interpretation
tantalum boride | molar mass
Result
Find the molar mass, M, for tantalum boride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: TaB Use the chemical formula, TaB, to count the number of atoms, N_i, for each element: | N_i B (boron) | 1 Ta (tantalum) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) B (boron) | 1 | 10.81 Ta (tantalum) | 1 | 180.94788 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) B (boron) | 1 | 10.81 | 1 × 10.81 = 10.81 Ta (tantalum) | 1 | 180.94788 | 1 × 180.94788 = 180.94788 M = 10.81 g/mol + 180.94788 g/mol = 191.76 g/mol
Unit conversion
0.19176 kg/mol (kilograms per mole)
Comparisons
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.99 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 192 u (unified atomic mass units) | 192 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 192