Input interpretation
(2s)-2-amino-3-oxo-4-phosphonooxybutanoate | molar mass
Result
Find the molar mass, M, for (2s)-2-amino-3-oxo-4-phosphonooxybutanoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_4H_8NO_7P Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 H (hydrogen) | 8 N (nitrogen) | 1 O (oxygen) | 7 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 H (hydrogen) | 8 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 7 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 H (hydrogen) | 8 | 1.008 | 8 × 1.008 = 8.064 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 7 | 15.999 | 7 × 15.999 = 111.993 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 48.044 g/mol + 8.064 g/mol + 14.007 g/mol + 111.993 g/mol + 30.973761998 g/mol = 213.082 g/mol
Unit conversion
0.21308 kg/mol (kilograms per mole)
Comparisons
≈ 0.3 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.1 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.5×10^-22 grams | 3.5×10^-25 kg (kilograms) | 213 u (unified atomic mass units) | 213 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 213