Input interpretation
![vanadium(II) sulfate heptahydrate | molar mass](../image_source/9bb10360883888ac68d702b32ee32e1b.png)
vanadium(II) sulfate heptahydrate | molar mass
Result
![Find the molar mass, M, for vanadium(II) sulfate heptahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: VSO_4·7H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 14 O (oxygen) | 11 S (sulfur) | 1 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 14 | 1.008 O (oxygen) | 11 | 15.999 S (sulfur) | 1 | 32.06 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 O (oxygen) | 11 | 15.999 | 11 × 15.999 = 175.989 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 14.112 g/mol + 175.989 g/mol + 32.06 g/mol + 50.9415 g/mol = 273.10 g/mol](../image_source/65078a408f596681989a119cd006563b.png)
Find the molar mass, M, for vanadium(II) sulfate heptahydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: VSO_4·7H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i H (hydrogen) | 14 O (oxygen) | 11 S (sulfur) | 1 V (vanadium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) H (hydrogen) | 14 | 1.008 O (oxygen) | 11 | 15.999 S (sulfur) | 1 | 32.06 V (vanadium) | 1 | 50.9415 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) H (hydrogen) | 14 | 1.008 | 14 × 1.008 = 14.112 O (oxygen) | 11 | 15.999 | 11 × 15.999 = 175.989 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 V (vanadium) | 1 | 50.9415 | 1 × 50.9415 = 50.9415 M = 14.112 g/mol + 175.989 g/mol + 32.06 g/mol + 50.9415 g/mol = 273.10 g/mol
Unit conversion
![0.2731 kg/mol (kilograms per mole)](../image_source/a1e7404c19e2a8012cbd6184aa7e3c6c.png)
0.2731 kg/mol (kilograms per mole)
Comparisons
![≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/c7031a7bd4728b4e60520b5fa36fb0ce.png)
≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/6f996d13dd190daee4e2786d9e28e536.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/8efe53901e24c60bd8f7662cfb15af81.png)
≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.5×10^-22 grams | 4.5×10^-25 kg (kilograms) | 273 u (unified atomic mass units) | 273 Da (daltons)](../image_source/7fa867ed914fd9f7b806075b55d18bb5.png)
Mass of a molecule m from m = M/N_A: | 4.5×10^-22 grams | 4.5×10^-25 kg (kilograms) | 273 u (unified atomic mass units) | 273 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 273](../image_source/32bf9dc07040f9e5e72b82bdf94b98a9.png)
Relative molecular mass M_r from M_r = M_u/M: | 273