methyl-d 3tribromoacetate

methyl-d 3tribromoacetate

formula | CBr_3CO_2CD_3 Hill formula | C_3D_3Br_3O_2 name | methyl-d 3tribromoacetate IUPAC name | 2, 2, 2-tribromoacetic acid trideuteriomethyl ester alternate names | 2, 2, 2-tribromoacetic acid trideuteriomethyl ester | trideuteriomethyl 2, 2, 2-tribromoacetate | trideuteriomethyl 2, 2, 2-tribromoethanoate mass fractions | Br (bromine) 0.764% | O (oxygen) 0.102% | C (carbon) 0.115% | H (hydrogen) 0.0193%

Draw the Lewis structure of methyl-d 3tribromoacetate. Start by drawing the overall structure of the molecule, ignoring potential double and triple bonds: Count the total valence electrons of the bromine (n_Br, val = 7), carbon (n_C, val = 4), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: 3 n_Br, val + 3 n_C, val + 3 n_H, val + 2 n_O, val = 48 Calculate the number of electrons needed to completely fill the valence shells for bromine (n_Br, full = 8), carbon (n_C, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): 3 n_Br, full + 3 n_C, full + 3 n_H, full + 2 n_O, full = 70 Subtracting these two numbers shows that 70 - 48 = 22 bonding electrons are needed. Each bond has two electrons, so in addition to the 10 bonds already present in the diagram add 1 bond. To minimize formal charge oxygen wants 2 bonds and carbon wants 4 bonds. Identify the atoms that want additional bonds and the number of electrons remaining on each atom: Fill in the 1 bond by pairing electrons between adjacent highlighted atoms: Answer: | |

3D structure

molar mass | 313.79 g/mol phase | liquid (at STP) boiling point | 103 °C (measured at 2000 Pa) density | 2.353 g/cm^3

density | 2.353 g/cm^3 refractive index | 1.558

H-2 | 3

CAS number | 207556-11-4 PubChem CID number | 16212809 PubChem SID number | 24867040 SMILES identifier | COC(=O)C(Br)(Br)Br InChI identifier | InChI=1/C3H3Br3O2/c1-8-2(7)3(4, 5)6/h1H3/i1D3 MDL number | MFCD00209605

flash point | 110 °C