Input interpretation
4-biphenylzinc bromide | molar mass
Result
Find the molar mass, M, for 4-biphenylzinc bromide: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_5C_6H_4ZnBr Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 12 H (hydrogen) | 9 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 12 | 12.011 H (hydrogen) | 9 | 1.008 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 79.904 g/mol + 144.132 g/mol + 9.072 g/mol + 65.38 g/mol = 298.49 g/mol
Unit conversion
0.2985 kg/mol (kilograms per mole)
Comparisons
≈ 0.41 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5×10^-22 grams | 5×10^-25 kg (kilograms) | 298 u (unified atomic mass units) | 298 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 298