Input interpretation
![bromperidol | molar mass](../image_source/8eb070375bf720f93d2720afcf8adf25.png)
bromperidol | molar mass
Result
![Find the molar mass, M, for bromperidol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_21H_23BrFNO_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 21 F (fluorine) | 1 H (hydrogen) | 23 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 21 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 23 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 21 | 12.011 | 21 × 12.011 = 252.231 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 23 | 1.008 | 23 × 1.008 = 23.184 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 79.904 g/mol + 252.231 g/mol + 18.998403163 g/mol + 23.184 g/mol + 14.007 g/mol + 31.998 g/mol = 420.322 g/mol](../image_source/d19e1d67828a39f422efdcaaf5c43be4.png)
Find the molar mass, M, for bromperidol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_21H_23BrFNO_2 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 1 C (carbon) | 21 F (fluorine) | 1 H (hydrogen) | 23 N (nitrogen) | 1 O (oxygen) | 2 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Br (bromine) | 1 | 79.904 C (carbon) | 21 | 12.011 F (fluorine) | 1 | 18.998403163 H (hydrogen) | 23 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 2 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Br (bromine) | 1 | 79.904 | 1 × 79.904 = 79.904 C (carbon) | 21 | 12.011 | 21 × 12.011 = 252.231 F (fluorine) | 1 | 18.998403163 | 1 × 18.998403163 = 18.998403163 H (hydrogen) | 23 | 1.008 | 23 × 1.008 = 23.184 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 2 | 15.999 | 2 × 15.999 = 31.998 M = 79.904 g/mol + 252.231 g/mol + 18.998403163 g/mol + 23.184 g/mol + 14.007 g/mol + 31.998 g/mol = 420.322 g/mol
Unit conversion
![0.42032 kg/mol (kilograms per mole)](../image_source/03c3d8cd1a54700d8a21870b7cfb41d9.png)
0.42032 kg/mol (kilograms per mole)
Comparisons
![≈ 0.58 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/14c05bb048c98cff176898f46e926c3d.png)
≈ 0.58 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/c9c58120f5294506a9599f19adf7f4de.png)
≈ 2.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.2 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/336ea80b84b8197c8f401d03f630675a.png)
≈ 7.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7×10^-22 grams | 7×10^-25 kg (kilograms) | 420 u (unified atomic mass units) | 420 Da (daltons)](../image_source/00d5e3644affa3b7308ef46c4251a25a.png)
Mass of a molecule m from m = M/N_A: | 7×10^-22 grams | 7×10^-25 kg (kilograms) | 420 u (unified atomic mass units) | 420 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 420](../image_source/2a5a748b8a926421e65125ddf90145c8.png)
Relative molecular mass M_r from M_r = M_u/M: | 420