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mass fractions of hydroxylamine

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hydroxylamine | elemental composition
hydroxylamine | elemental composition

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Find the elemental composition for hydroxylamine in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: NH_2OH Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule:  | number of atoms  H (hydrogen) | 3  N (nitrogen) | 1  O (oxygen) | 1  N_atoms = 3 + 1 + 1 = 5 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work:  | number of atoms | atom fraction  H (hydrogen) | 3 | 3/5  N (nitrogen) | 1 | 1/5  O (oxygen) | 1 | 1/5 Check: 3/5 + 1/5 + 1/5 = 1 Compute atom percents using the atom fractions:  | number of atoms | atom percent  H (hydrogen) | 3 | 3/5 × 100% = 60.0%  N (nitrogen) | 1 | 1/5 × 100% = 20.0%  O (oxygen) | 1 | 1/5 × 100% = 20.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | number of atoms | atom percent | atomic mass/u  H (hydrogen) | 3 | 60.0% | 1.008  N (nitrogen) | 1 | 20.0% | 14.007  O (oxygen) | 1 | 20.0% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m:  | number of atoms | atom percent | atomic mass/u | mass/u  H (hydrogen) | 3 | 60.0% | 1.008 | 3 × 1.008 = 3.024  N (nitrogen) | 1 | 20.0% | 14.007 | 1 × 14.007 = 14.007  O (oxygen) | 1 | 20.0% | 15.999 | 1 × 15.999 = 15.999  m = 3.024 u + 14.007 u + 15.999 u = 33.030 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work:  | number of atoms | atom percent | mass fraction  H (hydrogen) | 3 | 60.0% | 3.024/33.030  N (nitrogen) | 1 | 20.0% | 14.007/33.030  O (oxygen) | 1 | 20.0% | 15.999/33.030 Check: 3.024/33.030 + 14.007/33.030 + 15.999/33.030 = 1 Compute mass percents using the mass fractions: Answer: |   | | number of atoms | atom percent | mass percent  H (hydrogen) | 3 | 60.0% | 3.024/33.030 × 100% = 9.155%  N (nitrogen) | 1 | 20.0% | 14.007/33.030 × 100% = 42.41%  O (oxygen) | 1 | 20.0% | 15.999/33.030 × 100% = 48.44%
Find the elemental composition for hydroxylamine in terms of the atom and mass percents: atom percent = N_i/N_atoms × 100% mass percent = (N_im_i)/m × 100% Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i, m_i, N_atoms and m using these items. • Finally, compute the percents and check the results. Write the chemical formula: NH_2OH Use the chemical formula to count the number of atoms, N_i, for each element and find the total number of atoms, N_atoms, per molecule: | number of atoms H (hydrogen) | 3 N (nitrogen) | 1 O (oxygen) | 1 N_atoms = 3 + 1 + 1 = 5 Divide each N_i by N_atoms to calculate atom fractions. Then use the property that atom fractions must sum to one to check the work: | number of atoms | atom fraction H (hydrogen) | 3 | 3/5 N (nitrogen) | 1 | 1/5 O (oxygen) | 1 | 1/5 Check: 3/5 + 1/5 + 1/5 = 1 Compute atom percents using the atom fractions: | number of atoms | atom percent H (hydrogen) | 3 | 3/5 × 100% = 60.0% N (nitrogen) | 1 | 1/5 × 100% = 20.0% O (oxygen) | 1 | 1/5 × 100% = 20.0% Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | number of atoms | atom percent | atomic mass/u H (hydrogen) | 3 | 60.0% | 1.008 N (nitrogen) | 1 | 20.0% | 14.007 O (oxygen) | 1 | 20.0% | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: | number of atoms | atom percent | atomic mass/u | mass/u H (hydrogen) | 3 | 60.0% | 1.008 | 3 × 1.008 = 3.024 N (nitrogen) | 1 | 20.0% | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 20.0% | 15.999 | 1 × 15.999 = 15.999 m = 3.024 u + 14.007 u + 15.999 u = 33.030 u Divide the mass for each element by m to calculate mass fractions. Then use the property that mass fractions must sum to one to check the work: | number of atoms | atom percent | mass fraction H (hydrogen) | 3 | 60.0% | 3.024/33.030 N (nitrogen) | 1 | 20.0% | 14.007/33.030 O (oxygen) | 1 | 20.0% | 15.999/33.030 Check: 3.024/33.030 + 14.007/33.030 + 15.999/33.030 = 1 Compute mass percents using the mass fractions: Answer: | | | number of atoms | atom percent | mass percent H (hydrogen) | 3 | 60.0% | 3.024/33.030 × 100% = 9.155% N (nitrogen) | 1 | 20.0% | 14.007/33.030 × 100% = 42.41% O (oxygen) | 1 | 20.0% | 15.999/33.030 × 100% = 48.44%

Mass fraction pie chart

Mass fraction pie chart
Mass fraction pie chart