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molar mass of chrome violet g

Input interpretation

chrome violet g | molar mass
chrome violet g | molar mass

Result

Find the molar mass, M, for chrome violet g: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_11Na_3O_9 Use the chemical formula, C_22H_11Na_3O_9, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 22  H (hydrogen) | 11  Na (sodium) | 3  O (oxygen) | 9 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 22 | 12.011  H (hydrogen) | 11 | 1.008  Na (sodium) | 3 | 22.98976928  O (oxygen) | 9 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242  H (hydrogen) | 11 | 1.008 | 11 × 1.008 = 11.088  Na (sodium) | 3 | 22.98976928 | 3 × 22.98976928 = 68.96930784  O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991  M = 264.242 g/mol + 11.088 g/mol + 68.96930784 g/mol + 143.991 g/mol = 488.290 g/mol
Find the molar mass, M, for chrome violet g: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_22H_11Na_3O_9 Use the chemical formula, C_22H_11Na_3O_9, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 22 H (hydrogen) | 11 Na (sodium) | 3 O (oxygen) | 9 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 22 | 12.011 H (hydrogen) | 11 | 1.008 Na (sodium) | 3 | 22.98976928 O (oxygen) | 9 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 22 | 12.011 | 22 × 12.011 = 264.242 H (hydrogen) | 11 | 1.008 | 11 × 1.008 = 11.088 Na (sodium) | 3 | 22.98976928 | 3 × 22.98976928 = 68.96930784 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 M = 264.242 g/mol + 11.088 g/mol + 68.96930784 g/mol + 143.991 g/mol = 488.290 g/mol

Unit conversion

0.48829 kg/mol (kilograms per mole)
0.48829 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.68 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.68 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 2.5 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 8.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 8.4 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 8.1×10^-22 grams  | 8.1×10^-25 kg (kilograms)  | 488 u (unified atomic mass units)  | 488 Da (daltons)
Mass of a molecule m from m = M/N_A: | 8.1×10^-22 grams | 8.1×10^-25 kg (kilograms) | 488 u (unified atomic mass units) | 488 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 488
Relative molecular mass M_r from M_r = M_u/M: | 488