Input interpretation
![H_2 hydrogen + Ni2O3 ⟶ H_2O water + Ni nickel](../image_source/07698687563d7bcc8cfd9ed1988c6a78.png)
H_2 hydrogen + Ni2O3 ⟶ H_2O water + Ni nickel
Balanced equation
![Balance the chemical equation algebraically: H_2 + Ni2O3 ⟶ H_2O + Ni Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 Ni2O3 ⟶ c_3 H_2O + c_4 Ni Set the number of atoms in the reactants equal to the number of atoms in the products for H, Ni and O: H: | 2 c_1 = 2 c_3 Ni: | 2 c_2 = c_4 O: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 H_2 + Ni2O3 ⟶ 3 H_2O + 2 Ni](../image_source/bf5bf7c76df2fea4081e23efe8929863.png)
Balance the chemical equation algebraically: H_2 + Ni2O3 ⟶ H_2O + Ni Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2 + c_2 Ni2O3 ⟶ c_3 H_2O + c_4 Ni Set the number of atoms in the reactants equal to the number of atoms in the products for H, Ni and O: H: | 2 c_1 = 2 c_3 Ni: | 2 c_2 = c_4 O: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 H_2 + Ni2O3 ⟶ 3 H_2O + 2 Ni
Structures
![+ Ni2O3 ⟶ +](../image_source/129f3929a475fa93148e9c418a2feb94.png)
+ Ni2O3 ⟶ +
Names
![hydrogen + Ni2O3 ⟶ water + nickel](../image_source/398cc958e39d05612048f9ec81a9b61d.png)
hydrogen + Ni2O3 ⟶ water + nickel
Equilibrium constant
![Construct the equilibrium constant, K, expression for: H_2 + Ni2O3 ⟶ H_2O + Ni Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2 + Ni2O3 ⟶ 3 H_2O + 2 Ni Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 Ni2O3 | 1 | -1 H_2O | 3 | 3 Ni | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 3 | -3 | ([H2])^(-3) Ni2O3 | 1 | -1 | ([Ni2O3])^(-1) H_2O | 3 | 3 | ([H2O])^3 Ni | 2 | 2 | ([Ni])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-3) ([Ni2O3])^(-1) ([H2O])^3 ([Ni])^2 = (([H2O])^3 ([Ni])^2)/(([H2])^3 [Ni2O3])](../image_source/e2fc66357f48032eed3c1381e804f4a3.png)
Construct the equilibrium constant, K, expression for: H_2 + Ni2O3 ⟶ H_2O + Ni Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 H_2 + Ni2O3 ⟶ 3 H_2O + 2 Ni Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 Ni2O3 | 1 | -1 H_2O | 3 | 3 Ni | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2 | 3 | -3 | ([H2])^(-3) Ni2O3 | 1 | -1 | ([Ni2O3])^(-1) H_2O | 3 | 3 | ([H2O])^3 Ni | 2 | 2 | ([Ni])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2])^(-3) ([Ni2O3])^(-1) ([H2O])^3 ([Ni])^2 = (([H2O])^3 ([Ni])^2)/(([H2])^3 [Ni2O3])
Rate of reaction
![Construct the rate of reaction expression for: H_2 + Ni2O3 ⟶ H_2O + Ni Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2 + Ni2O3 ⟶ 3 H_2O + 2 Ni Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 Ni2O3 | 1 | -1 H_2O | 3 | 3 Ni | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 3 | -3 | -1/3 (Δ[H2])/(Δt) Ni2O3 | 1 | -1 | -(Δ[Ni2O3])/(Δt) H_2O | 3 | 3 | 1/3 (Δ[H2O])/(Δt) Ni | 2 | 2 | 1/2 (Δ[Ni])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[H2])/(Δt) = -(Δ[Ni2O3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = 1/2 (Δ[Ni])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)](../image_source/4e730b584190bc8cf48a4464d6e9bd9e.png)
Construct the rate of reaction expression for: H_2 + Ni2O3 ⟶ H_2O + Ni Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 H_2 + Ni2O3 ⟶ 3 H_2O + 2 Ni Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2 | 3 | -3 Ni2O3 | 1 | -1 H_2O | 3 | 3 Ni | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2 | 3 | -3 | -1/3 (Δ[H2])/(Δt) Ni2O3 | 1 | -1 | -(Δ[Ni2O3])/(Δt) H_2O | 3 | 3 | 1/3 (Δ[H2O])/(Δt) Ni | 2 | 2 | 1/2 (Δ[Ni])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[H2])/(Δt) = -(Δ[Ni2O3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = 1/2 (Δ[Ni])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Chemical names and formulas
![| hydrogen | Ni2O3 | water | nickel formula | H_2 | Ni2O3 | H_2O | Ni name | hydrogen | | water | nickel IUPAC name | molecular hydrogen | | water | nickel](../image_source/09925429a6ade9a28ce68a0a5910f619.png)
| hydrogen | Ni2O3 | water | nickel formula | H_2 | Ni2O3 | H_2O | Ni name | hydrogen | | water | nickel IUPAC name | molecular hydrogen | | water | nickel
Substance properties
![| hydrogen | Ni2O3 | water | nickel molar mass | 2.016 g/mol | 165.38 g/mol | 18.015 g/mol | 58.6934 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -259.2 °C | | 0 °C | 1453 °C boiling point | -252.8 °C | | 99.9839 °C | 2732 °C density | 8.99×10^-5 g/cm^3 (at 0 °C) | | 1 g/cm^3 | 8.908 g/cm^3 solubility in water | | | | insoluble surface tension | | | 0.0728 N/m | dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | odorless | | odorless | odorless](../image_source/0aa8662eaf0022d7d395e58fe5ae1f07.png)
| hydrogen | Ni2O3 | water | nickel molar mass | 2.016 g/mol | 165.38 g/mol | 18.015 g/mol | 58.6934 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -259.2 °C | | 0 °C | 1453 °C boiling point | -252.8 °C | | 99.9839 °C | 2732 °C density | 8.99×10^-5 g/cm^3 (at 0 °C) | | 1 g/cm^3 | 8.908 g/cm^3 solubility in water | | | | insoluble surface tension | | | 0.0728 N/m | dynamic viscosity | 8.9×10^-6 Pa s (at 25 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | odorless | | odorless | odorless
Units