Input interpretation
water + nitrogen trioxide ⟶ nitrous acid
Balanced equation
Balance the chemical equation algebraically: + ⟶ Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and N: H: | 2 c_1 = c_3 O: | c_1 + 3 c_2 = 2 c_3 N: | 2 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | + ⟶ 2
Structures
+ ⟶
Names
water + nitrogen trioxide ⟶ nitrous acid
Chemical names and formulas
| water | nitrogen trioxide | nitrous acid Hill formula | H_2O | N_2O_3 | HNO_2 name | water | nitrogen trioxide | nitrous acid IUPAC name | water | nitramide | nitrous acid
Substance properties
| water | nitrogen trioxide | nitrous acid molar mass | 18.015 g/mol | 76.011 g/mol | 47.013 g/mol phase | liquid (at STP) | gas (at STP) | melting point | 0 °C | -111 °C | boiling point | 99.9839 °C | -27 °C | density | 1 g/cm^3 | 1.4 g/cm^3 (at 2 °C) | solubility in water | | very soluble | surface tension | 0.0728 N/m | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | odor | odorless | |
Units
