Input interpretation
D-(+)-glucose | relative molecular mass
Result
Find the relative molecular mass, M_r, for D-(+)-glucose: M_r = sum _iN_im_i/m_u Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_12O_6 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 12 O (oxygen) | 6 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table. Since m_i is divided by the atomic mass constant, m_u, the result is a unitless relative atomic mass: | N_i | m_i/m_u C (carbon) | 6 | 12.011 H (hydrogen) | 12 | 1.008 O (oxygen) | 6 | 15.999 Multiply N_i by m_i/m_u to compute the relative mass for each element. Then sum those values to compute the relative molecular mass, M_r: Answer: | | | N_i | m_i/m_u | relative mass C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 M_r = 72.066 + 12.096 + 95.994 = 180.156
Comparisons
≈ ( 0.25 ≈ 1/4 ) × relative molecular mass of fullerene ( ≈ 721 )
≈ 0.93 × relative molecular mass of caffeine ( ≈ 194 )
≈ 3.1 × relative molecular mass of sodium chloride ( ≈ 58 )
Corresponding quantities
Molar mass M from M = M_uM_r: | 180 g/mol (grams per mole)
Molecular mass m from m = M_rM_u/N_A: | 3×10^-22 grams | 3×10^-25 kg (kilograms)