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H2O2 + H2SeO3 = H2O + H2SeO4

Input interpretation

H_2O_2 (hydrogen peroxide) + H_2SeO_3 (selenious acid) ⟶ H_2O (water) + H_2SeO_4 (selenic acid)
H_2O_2 (hydrogen peroxide) + H_2SeO_3 (selenious acid) ⟶ H_2O (water) + H_2SeO_4 (selenic acid)

Balanced equation

Balance the chemical equation algebraically: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O_2 + c_2 H_2SeO_3 ⟶ c_3 H_2O + c_4 H_2SeO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and Se: H: | 2 c_1 + 2 c_2 = 2 c_3 + 2 c_4 O: | 2 c_1 + 3 c_2 = c_3 + 4 c_4 Se: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4
Balance the chemical equation algebraically: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O_2 + c_2 H_2SeO_3 ⟶ c_3 H_2O + c_4 H_2SeO_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O and Se: H: | 2 c_1 + 2 c_2 = 2 c_3 + 2 c_4 O: | 2 c_1 + 3 c_2 = c_3 + 4 c_4 Se: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 c_3 = 1 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4

Structures

 + ⟶ +
+ ⟶ +

Names

hydrogen peroxide + selenious acid ⟶ water + selenic acid
hydrogen peroxide + selenious acid ⟶ water + selenic acid

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 1 | -1 H_2SeO_3 | 1 | -1 H_2O | 1 | 1 H_2SeO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O_2 | 1 | -1 | ([H2O2])^(-1) H_2SeO_3 | 1 | -1 | ([H2SeO3])^(-1) H_2O | 1 | 1 | [H2O] H_2SeO_4 | 1 | 1 | [H2SeO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([H2O2])^(-1) ([H2SeO3])^(-1) [H2O] [H2SeO4] = ([H2O] [H2SeO4])/([H2O2] [H2SeO3])
Construct the equilibrium constant, K, expression for: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 1 | -1 H_2SeO_3 | 1 | -1 H_2O | 1 | 1 H_2SeO_4 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O_2 | 1 | -1 | ([H2O2])^(-1) H_2SeO_3 | 1 | -1 | ([H2SeO3])^(-1) H_2O | 1 | 1 | [H2O] H_2SeO_4 | 1 | 1 | [H2SeO4] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O2])^(-1) ([H2SeO3])^(-1) [H2O] [H2SeO4] = ([H2O] [H2SeO4])/([H2O2] [H2SeO3])

Rate of reaction

Construct the rate of reaction expression for: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 1 | -1 H_2SeO_3 | 1 | -1 H_2O | 1 | 1 H_2SeO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O_2 | 1 | -1 | -(Δ[H2O2])/(Δt) H_2SeO_3 | 1 | -1 | -(Δ[H2SeO3])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) H_2SeO_4 | 1 | 1 | (Δ[H2SeO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[H2O2])/(Δt) = -(Δ[H2SeO3])/(Δt) = (Δ[H2O])/(Δt) = (Δ[H2SeO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: H_2O_2 + H_2SeO_3 ⟶ H_2O + H_2SeO_4 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O_2 | 1 | -1 H_2SeO_3 | 1 | -1 H_2O | 1 | 1 H_2SeO_4 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O_2 | 1 | -1 | -(Δ[H2O2])/(Δt) H_2SeO_3 | 1 | -1 | -(Δ[H2SeO3])/(Δt) H_2O | 1 | 1 | (Δ[H2O])/(Δt) H_2SeO_4 | 1 | 1 | (Δ[H2SeO4])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[H2O2])/(Δt) = -(Δ[H2SeO3])/(Δt) = (Δ[H2O])/(Δt) = (Δ[H2SeO4])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | hydrogen peroxide | selenious acid | water | selenic acid formula | H_2O_2 | H_2SeO_3 | H_2O | H_2SeO_4 Hill formula | H_2O_2 | H_2O_3Se | H_2O | H_2O_4Se name | hydrogen peroxide | selenious acid | water | selenic acid IUPAC name | hydrogen peroxide | selenous acid | water | selenic acid
| hydrogen peroxide | selenious acid | water | selenic acid formula | H_2O_2 | H_2SeO_3 | H_2O | H_2SeO_4 Hill formula | H_2O_2 | H_2O_3Se | H_2O | H_2O_4Se name | hydrogen peroxide | selenious acid | water | selenic acid IUPAC name | hydrogen peroxide | selenous acid | water | selenic acid

Substance properties

 | hydrogen peroxide | selenious acid | water | selenic acid molar mass | 34.014 g/mol | 128.98 g/mol | 18.015 g/mol | 144.98 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) |  melting point | -0.43 °C | 70 °C | 0 °C |  boiling point | 150.2 °C | 315 °C | 99.9839 °C |  density | 1.44 g/cm^3 | 3.004 g/cm^3 | 1 g/cm^3 | 2.511 g/cm^3 solubility in water | miscible | | |  surface tension | 0.0804 N/m | | 0.0728 N/m |  dynamic viscosity | 0.001249 Pa s (at 20 °C) | | 8.9×10^-4 Pa s (at 25 °C) |  odor | | | odorless |
| hydrogen peroxide | selenious acid | water | selenic acid molar mass | 34.014 g/mol | 128.98 g/mol | 18.015 g/mol | 144.98 g/mol phase | liquid (at STP) | solid (at STP) | liquid (at STP) | melting point | -0.43 °C | 70 °C | 0 °C | boiling point | 150.2 °C | 315 °C | 99.9839 °C | density | 1.44 g/cm^3 | 3.004 g/cm^3 | 1 g/cm^3 | 2.511 g/cm^3 solubility in water | miscible | | | surface tension | 0.0804 N/m | | 0.0728 N/m | dynamic viscosity | 0.001249 Pa s (at 20 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units