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FeH2SO4 = FeSO4H2

Input interpretation

FeH2SO4 ⟶ FeSO4H2
FeH2SO4 ⟶ FeSO4H2

Balanced equation

Balance the chemical equation algebraically: FeH2SO4 ⟶ FeSO4H2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 FeH2SO4 ⟶ c_2 FeSO4H2 Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, H, S and O: Fe: | c_1 = c_2 H: | 2 c_1 = 2 c_2 S: | c_1 = c_2 O: | 4 c_1 = 4 c_2 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | FeH2SO4 ⟶ FeSO4H2
Balance the chemical equation algebraically: FeH2SO4 ⟶ FeSO4H2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 FeH2SO4 ⟶ c_2 FeSO4H2 Set the number of atoms in the reactants equal to the number of atoms in the products for Fe, H, S and O: Fe: | c_1 = c_2 H: | 2 c_1 = 2 c_2 S: | c_1 = c_2 O: | 4 c_1 = 4 c_2 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_1 = 1 and solve the system of equations for the remaining coefficients: c_1 = 1 c_2 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | FeH2SO4 ⟶ FeSO4H2

Structures

FeH2SO4 ⟶ FeSO4H2
FeH2SO4 ⟶ FeSO4H2

Names

FeH2SO4 ⟶ FeSO4H2
FeH2SO4 ⟶ FeSO4H2

Equilibrium constant

Construct the equilibrium constant, K, expression for: FeH2SO4 ⟶ FeSO4H2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: FeH2SO4 ⟶ FeSO4H2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeH2SO4 | 1 | -1 FeSO4H2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression FeH2SO4 | 1 | -1 | ([FeH2SO4])^(-1) FeSO4H2 | 1 | 1 | [FeSO4H2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([FeH2SO4])^(-1) [FeSO4H2] = ([FeSO4H2])/([FeH2SO4])
Construct the equilibrium constant, K, expression for: FeH2SO4 ⟶ FeSO4H2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: FeH2SO4 ⟶ FeSO4H2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeH2SO4 | 1 | -1 FeSO4H2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression FeH2SO4 | 1 | -1 | ([FeH2SO4])^(-1) FeSO4H2 | 1 | 1 | [FeSO4H2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([FeH2SO4])^(-1) [FeSO4H2] = ([FeSO4H2])/([FeH2SO4])

Rate of reaction

Construct the rate of reaction expression for: FeH2SO4 ⟶ FeSO4H2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: FeH2SO4 ⟶ FeSO4H2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeH2SO4 | 1 | -1 FeSO4H2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term FeH2SO4 | 1 | -1 | -(Δ[FeH2SO4])/(Δt) FeSO4H2 | 1 | 1 | (Δ[FeSO4H2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -(Δ[FeH2SO4])/(Δt) = (Δ[FeSO4H2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: FeH2SO4 ⟶ FeSO4H2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: FeH2SO4 ⟶ FeSO4H2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i FeH2SO4 | 1 | -1 FeSO4H2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term FeH2SO4 | 1 | -1 | -(Δ[FeH2SO4])/(Δt) FeSO4H2 | 1 | 1 | (Δ[FeSO4H2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -(Δ[FeH2SO4])/(Δt) = (Δ[FeSO4H2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | FeH2SO4 | FeSO4H2 formula | FeH2SO4 | FeSO4H2 Hill formula | H2FeO4S | H2FeO4S
| FeH2SO4 | FeSO4H2 formula | FeH2SO4 | FeSO4H2 Hill formula | H2FeO4S | H2FeO4S

Substance properties

 | FeH2SO4 | FeSO4H2 molar mass | 153.92 g/mol | 153.92 g/mol
| FeH2SO4 | FeSO4H2 molar mass | 153.92 g/mol | 153.92 g/mol

Units