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molar mass of lithium nitrate

Input interpretation

lithium nitrate | molar mass
lithium nitrate | molar mass

Result

Find the molar mass, M, for lithium nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: LiNO_3 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  Li (lithium) | 1  N (nitrogen) | 1  O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  Li (lithium) | 1 | 6.94  N (nitrogen) | 1 | 14.007  O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94  N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  M = 6.94 g/mol + 14.007 g/mol + 47.997 g/mol = 68.94 g/mol
Find the molar mass, M, for lithium nitrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: LiNO_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i Li (lithium) | 1 N (nitrogen) | 1 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) Li (lithium) | 1 | 6.94 N (nitrogen) | 1 | 14.007 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) Li (lithium) | 1 | 6.94 | 1 × 6.94 = 6.94 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 6.94 g/mol + 14.007 g/mol + 47.997 g/mol = 68.94 g/mol

Unit conversion

0.06894 kg/mol (kilograms per mole)
0.06894 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.096 ≈ 1/10 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.096 ≈ 1/10 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.36 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.36 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 1.2 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 1.2 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 1.1×10^-22 grams  | 1.1×10^-25 kg (kilograms)  | 69 u (unified atomic mass units)  | 69 Da (daltons)
Mass of a molecule m from m = M/N_A: | 1.1×10^-22 grams | 1.1×10^-25 kg (kilograms) | 69 u (unified atomic mass units) | 69 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 69
Relative molecular mass M_r from M_r = M_u/M: | 69