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molar mass of 4-methyl-5-thiazoleethanol

Input interpretation

4-methyl-5-thiazoleethanol | molar mass
4-methyl-5-thiazoleethanol | molar mass

Result

Find the molar mass, M, for 4-methyl-5-thiazoleethanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_9NOS Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 6  H (hydrogen) | 9  N (nitrogen) | 1  O (oxygen) | 1  S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 6 | 12.011  H (hydrogen) | 9 | 1.008  N (nitrogen) | 1 | 14.007  O (oxygen) | 1 | 15.999  S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066  H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072  N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007  O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999  S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06  M = 72.066 g/mol + 9.072 g/mol + 14.007 g/mol + 15.999 g/mol + 32.06 g/mol = 143.20 g/mol
Find the molar mass, M, for 4-methyl-5-thiazoleethanol: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_9NOS Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 H (hydrogen) | 9 N (nitrogen) | 1 O (oxygen) | 1 S (sulfur) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 H (hydrogen) | 9 | 1.008 N (nitrogen) | 1 | 14.007 O (oxygen) | 1 | 15.999 S (sulfur) | 1 | 32.06 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 H (hydrogen) | 9 | 1.008 | 9 × 1.008 = 9.072 N (nitrogen) | 1 | 14.007 | 1 × 14.007 = 14.007 O (oxygen) | 1 | 15.999 | 1 × 15.999 = 15.999 S (sulfur) | 1 | 32.06 | 1 × 32.06 = 32.06 M = 72.066 g/mol + 9.072 g/mol + 14.007 g/mol + 15.999 g/mol + 32.06 g/mol = 143.20 g/mol

Unit conversion

0.1432 kg/mol (kilograms per mole)
0.1432 kg/mol (kilograms per mole)

Comparisons

 ≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
≈ ( 0.2 ≈ 1/5 ) × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 0.74 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 0.74 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 2.5 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 2.4×10^-22 grams  | 2.4×10^-25 kg (kilograms)  | 143 u (unified atomic mass units)  | 143 Da (daltons)
Mass of a molecule m from m = M/N_A: | 2.4×10^-22 grams | 2.4×10^-25 kg (kilograms) | 143 u (unified atomic mass units) | 143 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 143
Relative molecular mass M_r from M_r = M_u/M: | 143