Search

critical pressure of cesium

Input interpretation

cesium | critical pressure
cesium | critical pressure

Result

9.4 MPa (megapascals)
9.4 MPa (megapascals)

Unit conversions

9.4×10^6 Pa (pascals)
9.4×10^6 Pa (pascals)
9.4×10^6 N/m^2 (newtons per square meter)
9.4×10^6 N/m^2 (newtons per square meter)
960 tf/m^2 (metric tons-force per square meter)
960 tf/m^2 (metric tons-force per square meter)
93 atm (atmospheres)  (unit officially deprecated)
93 atm (atmospheres) (unit officially deprecated)
94 bars
94 bars
940 dbar (decibars)
940 dbar (decibars)
0.094 kbar (kilobars)
0.094 kbar (kilobars)
960 m WC (meters of water column)
960 m WC (meters of water column)
0.96 km WC (kilometers of water column)
0.96 km WC (kilometers of water column)
1400 psi (pounds-force per square inch)
1400 psi (pounds-force per square inch)
200000 lbf/ft^2 (pounds-force per square foot)
200000 lbf/ft^2 (pounds-force per square foot)

Comparisons as pressure

 ≈ (0.3 to 1.3) × nozzle pressure of a pressure washer ( 6.9×10^6 to 2.7×10^7 Pa )
≈ (0.3 to 1.3) × nozzle pressure of a pressure washer ( 6.9×10^6 to 2.7×10^7 Pa )
 ≈ 0.94 × pressure exerted by a 45 kg woman wearing stiletto heels ( ≈ 1×10^7 Pa )
≈ 0.94 × pressure exerted by a 45 kg woman wearing stiletto heels ( ≈ 1×10^7 Pa )
 ≈ atmospheric pressure on the surface of Venus ( ≈ 9 MPa )
≈ atmospheric pressure on the surface of Venus ( ≈ 9 MPa )

Corresponding quantity

Depth of water d giving gauge pressure p_e from p_e = ρ_(H_2O)gh:  | 0.96 km (kilometers)  | 0.6 miles  | 3145 feet  | (assuming maximum water density ≈ 1000 kg/m^3)
Depth of water d giving gauge pressure p_e from p_e = ρ_(H_2O)gh: | 0.96 km (kilometers) | 0.6 miles | 3145 feet | (assuming maximum water density ≈ 1000 kg/m^3)