Input interpretation
![deuterium chloride](../image_source/0ead91e3b3569a62616be63ea390286e.png)
deuterium chloride
Chemical names and formulas
![formula | DCl Hill formula | Cl(1H) name | deuterium chloride alternate names | hydrochloric acid-d solution mass fractions | Cl (chlorine) 0.972% | H (hydrogen) 0.0276%](../image_source/e0b3863c0ab78b83d07b85f18007dab8.png)
formula | DCl Hill formula | Cl(1H) name | deuterium chloride alternate names | hydrochloric acid-d solution mass fractions | Cl (chlorine) 0.972% | H (hydrogen) 0.0276%
Lewis structure
![Draw the Lewis structure of deuterium chloride. Start by drawing the overall structure of the molecule: Count the total valence electrons of the chlorine (n_Cl, val = 7) and hydrogen (n_H, val = 1) atoms: n_Cl, val + n_H, val = 8 Calculate the number of electrons needed to completely fill the valence shells for chlorine (n_Cl, full = 8) and hydrogen (n_H, full = 2): n_Cl, full + n_H, full = 10 Subtracting these two numbers shows that 10 - 8 = 2 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There is 1 bond and hence 2 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 8 - 2 = 6 electrons left to draw: Answer: | |](../image_source/8175abb778693ed2792df6e86ec74202.png)
Draw the Lewis structure of deuterium chloride. Start by drawing the overall structure of the molecule: Count the total valence electrons of the chlorine (n_Cl, val = 7) and hydrogen (n_H, val = 1) atoms: n_Cl, val + n_H, val = 8 Calculate the number of electrons needed to completely fill the valence shells for chlorine (n_Cl, full = 8) and hydrogen (n_H, full = 2): n_Cl, full + n_H, full = 10 Subtracting these two numbers shows that 10 - 8 = 2 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There is 1 bond and hence 2 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 8 - 2 = 6 electrons left to draw: Answer: | |
3D structure
![3D structure](../image_source/8d17d60f9b9c34c919b9f8dd3e3e18b7.png)
3D structure
Basic properties
![molar mass | 36.46 g/mol phase | liquid (at STP) boiling point | 108 °C density | 1.181 g/cm^3](../image_source/ff64e543090a4b057437024797341dbc.png)
molar mass | 36.46 g/mol phase | liquid (at STP) boiling point | 108 °C density | 1.181 g/cm^3
Units
Liquid properties (at STP)
![density | 1.181 g/cm^3 refractive index | 1.373](../image_source/a3599a9a5b017c52d516c4b1762eb463.png)
density | 1.181 g/cm^3 refractive index | 1.373
Units
Non-standard atom properties
![H-1 | 1](../image_source/e673aafe1d68342af5677fbdf954d961.png)
H-1 | 1
Chemical identifiers
![CAS number | 7698-05-7 PubChem CID number | 123256 SMILES identifier | Cl InChI identifier | InChI=1/ClH/h1H/i/hH/f/i1H MDL number | MFCD00044642](../image_source/e9e320a702330890ab25fe9c755fd88d.png)
CAS number | 7698-05-7 PubChem CID number | 123256 SMILES identifier | Cl InChI identifier | InChI=1/ClH/h1H/i/hH/f/i1H MDL number | MFCD00044642