Input interpretation
![(3-chloropropyl)triethoxysilane | molar mass](../image_source/5dab3cca2785278fd5f2391703e1fb05.png)
(3-chloropropyl)triethoxysilane | molar mass
Result
![Find the molar mass, M, for (3-chloropropyl)triethoxysilane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ClCH_2CH_2CH_2SI(OCH_2CH_3)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 Cl (chlorine) | 1 H (hydrogen) | 21 O (oxygen) | 3 Si (silicon) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 21 | 1.008 O (oxygen) | 3 | 15.999 Si (silicon) | 1 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Si (silicon) | 1 | 28.085 | 1 × 28.085 = 28.085 M = 108.099 g/mol + 35.45 g/mol + 21.168 g/mol + 47.997 g/mol + 28.085 g/mol = 240.80 g/mol](../image_source/2859e8501c4dad13266cb777490cd36f.png)
Find the molar mass, M, for (3-chloropropyl)triethoxysilane: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ClCH_2CH_2CH_2SI(OCH_2CH_3)_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 9 Cl (chlorine) | 1 H (hydrogen) | 21 O (oxygen) | 3 Si (silicon) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 9 | 12.011 Cl (chlorine) | 1 | 35.45 H (hydrogen) | 21 | 1.008 O (oxygen) | 3 | 15.999 Si (silicon) | 1 | 28.085 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 9 | 12.011 | 9 × 12.011 = 108.099 Cl (chlorine) | 1 | 35.45 | 1 × 35.45 = 35.45 H (hydrogen) | 21 | 1.008 | 21 × 1.008 = 21.168 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 Si (silicon) | 1 | 28.085 | 1 × 28.085 = 28.085 M = 108.099 g/mol + 35.45 g/mol + 21.168 g/mol + 47.997 g/mol + 28.085 g/mol = 240.80 g/mol
Unit conversion
![0.2408 kg/mol (kilograms per mole)](../image_source/ffc896d77b5594d6ab61a6ec81cab584.png)
0.2408 kg/mol (kilograms per mole)
Comparisons
![≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/0a9f33f28f80183f44bc8ab4961025d7.png)
≈ 0.33 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/2d845487986bbc4b5c75d483f2875b1d.png)
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/caaed976b82483d03f80d75ca158668a.png)
≈ 4.1 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 241 u (unified atomic mass units) | 241 Da (daltons)](../image_source/91a3e5d2f692eead499e07385fdfba5d.png)
Mass of a molecule m from m = M/N_A: | 4×10^-22 grams | 4×10^-25 kg (kilograms) | 241 u (unified atomic mass units) | 241 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 241](../image_source/bed0884b2848a9921420fc57878f8d2d.png)
Relative molecular mass M_r from M_r = M_u/M: | 241