Input interpretation
![lead(IV) acetate | molar mass](../image_source/ef9864c4e2359cbbb308e6dc1ca93623.png)
lead(IV) acetate | molar mass
Result
![Find the molar mass, M, for lead(IV) acetate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pb(CH_3CO_2)_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 H (hydrogen) | 12 O (oxygen) | 8 Pb (lead) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 H (hydrogen) | 12 | 1.008 O (oxygen) | 8 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 M = 96.088 g/mol + 12.096 g/mol + 127.992 g/mol + 207.2 g/mol = 443.4 g/mol](../image_source/09f525b2b5c8d7b838ddf4fd3fb00caf.png)
Find the molar mass, M, for lead(IV) acetate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Pb(CH_3CO_2)_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 8 H (hydrogen) | 12 O (oxygen) | 8 Pb (lead) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 8 | 12.011 H (hydrogen) | 12 | 1.008 O (oxygen) | 8 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 8 | 12.011 | 8 × 12.011 = 96.088 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 8 | 15.999 | 8 × 15.999 = 127.992 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 M = 96.088 g/mol + 12.096 g/mol + 127.992 g/mol + 207.2 g/mol = 443.4 g/mol
Unit conversion
![0.4434 kg/mol (kilograms per mole)](../image_source/df7117d047373fa722077a4a668c689e.png)
0.4434 kg/mol (kilograms per mole)
Comparisons
![≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/2d1ab18831f8e6d08bb97aae039c42ce.png)
≈ 0.62 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/da13da1e247e15d7345887571d5bac1e.png)
≈ 2.3 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 7.6 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/f1509e7836958ddbbc3a76e687ebfb30.png)
≈ 7.6 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 7.4×10^-22 grams | 7.4×10^-25 kg (kilograms) | 443 u (unified atomic mass units) | 443 Da (daltons)](../image_source/d1860167bdb278a93186f5a3d4d787fb.png)
Mass of a molecule m from m = M/N_A: | 7.4×10^-22 grams | 7.4×10^-25 kg (kilograms) | 443 u (unified atomic mass units) | 443 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 443](../image_source/169f45c3e94e88ef73b8af3003dd9edf.png)
Relative molecular mass M_r from M_r = M_u/M: | 443