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molecular mass of (5z,9e,14z)-(8xi,11xi,12s)-8,11,12-trihydroxyicosa-5,9,14-trienoate

Input interpretation

(5z, 9e, 14z)-(8xi, 11xi, 12s)-8, 11, 12-trihydroxyicosa-5, 9, 14-trienoate | molecular mass
(5z, 9e, 14z)-(8xi, 11xi, 12s)-8, 11, 12-trihydroxyicosa-5, 9, 14-trienoate | molecular mass

Result

Find the molecular mass, m, for (5z, 9e, 14z)-(8xi, 11xi, 12s)-8, 11, 12-trihydroxyicosa-5, 9, 14-trienoate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_34O_5 Use the chemical formula to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 20  H (hydrogen) | 33  O (oxygen) | 5 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | N_i | m_i/u  C (carbon) | 20 | 12.011  H (hydrogen) | 33 | 1.008  O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: |   | | N_i | m_i/u | mass/u  C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220  H (hydrogen) | 33 | 1.008 | 33 × 1.008 = 33.264  O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995  m = 240.220 u + 33.264 u + 79.995 u = 353.479 u
Find the molecular mass, m, for (5z, 9e, 14z)-(8xi, 11xi, 12s)-8, 11, 12-trihydroxyicosa-5, 9, 14-trienoate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_20H_34O_5 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 20 H (hydrogen) | 33 O (oxygen) | 5 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u C (carbon) | 20 | 12.011 H (hydrogen) | 33 | 1.008 O (oxygen) | 5 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u C (carbon) | 20 | 12.011 | 20 × 12.011 = 240.220 H (hydrogen) | 33 | 1.008 | 33 × 1.008 = 33.264 O (oxygen) | 5 | 15.999 | 5 × 15.999 = 79.995 m = 240.220 u + 33.264 u + 79.995 u = 353.479 u

Unit conversions

353.48 Da (daltons)
353.48 Da (daltons)
0.35348 kDa (kilodaltons)
0.35348 kDa (kilodaltons)
5.87×10^-22 grams
5.87×10^-22 grams
5.87×10^-25 kg (kilograms)
5.87×10^-25 kg (kilograms)
353.49 chemical atomic mass units  (unit officially deprecated)
353.49 chemical atomic mass units (unit officially deprecated)
353.59 physical atomic mass units  (unit officially deprecated)
353.59 physical atomic mass units (unit officially deprecated)

Comparisons as mass of molecule

 ≈ 0.49 × molecular mass of fullerene ( ≈ 721 u )
≈ 0.49 × molecular mass of fullerene ( ≈ 721 u )
 ≈ 1.8 × molecular mass of caffeine ( ≈ 194 u )
≈ 1.8 × molecular mass of caffeine ( ≈ 194 u )
 ≈ 6 × molecular mass of sodium chloride ( ≈ 58 u )
≈ 6 × molecular mass of sodium chloride ( ≈ 58 u )

Corresponding quantities

Relative atomic mass A_r from A_r = m_aN_A/M_u:  | 353
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 353
Molar mass M from M = m_aN_A:  | 353 g/mol (grams per mole)
Molar mass M from M = m_aN_A: | 353 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u:  | 353
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 353
Molar mass M from M = m_mN_A:  | 353 g/mol (grams per mole)
Molar mass M from M = m_mN_A: | 353 g/mol (grams per mole)