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name of 1,1,2-trimethylcyclohexane

Input interpretation

1, 1, 2-trimethylcyclohexane
1, 1, 2-trimethylcyclohexane

Chemical names and formulas

formula | C_9H_18 name | 1, 1, 2-trimethylcyclohexane alternate names | 2, 2, 3-trimethylcyclohexane | cyclohexane, 1, 1, 2-trimethyl- mass fractions | C (carbon) 85.6% | H (hydrogen) 14.4%
formula | C_9H_18 name | 1, 1, 2-trimethylcyclohexane alternate names | 2, 2, 3-trimethylcyclohexane | cyclohexane, 1, 1, 2-trimethyl- mass fractions | C (carbon) 85.6% | H (hydrogen) 14.4%

Lewis structure

Draw the Lewis structure of 1, 1, 2-trimethylcyclohexane. Start by drawing the overall structure of the molecule:  Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 9 n_C, val + 18 n_H, val = 54 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 9 n_C, full + 18 n_H, full = 108 Subtracting these two numbers shows that 108 - 54 = 54 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 27 bonds and hence 54 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 54 - 54 = 0 electrons left to draw and the diagram is complete: Answer: |   |
Draw the Lewis structure of 1, 1, 2-trimethylcyclohexane. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 9 n_C, val + 18 n_H, val = 54 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 9 n_C, full + 18 n_H, full = 108 Subtracting these two numbers shows that 108 - 54 = 54 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 27 bonds and hence 54 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 54 - 54 = 0 electrons left to draw and the diagram is complete: Answer: | |

3D structure

3D structure
3D structure

Basic properties

molar mass | 126.24 g/mol phase | liquid (at STP) melting point | -29 °C boiling point | 145.2 °C density | 0.7963 g/cm^3 solubility in water | insoluble
molar mass | 126.24 g/mol phase | liquid (at STP) melting point | -29 °C boiling point | 145.2 °C density | 0.7963 g/cm^3 solubility in water | insoluble

Units

Liquid properties (at STP)

density | 0.7963 g/cm^3 refractive index | 1.4382
density | 0.7963 g/cm^3 refractive index | 1.4382

Units

Chemical identifiers

CAS number | 7094-26-0 Beilstein number | 1900445 PubChem CID number | 35363 SMILES identifier | CC1CCCCC1(C)C InChI identifier | InChI=1/C9H18/c1-8-6-4-5-7-9(8, 2)3/h8H, 4-7H2, 1-3H3 EU number | 230-400-2 NSC number | 73964
CAS number | 7094-26-0 Beilstein number | 1900445 PubChem CID number | 35363 SMILES identifier | CC1CCCCC1(C)C InChI identifier | InChI=1/C9H18/c1-8-6-4-5-7-9(8, 2)3/h8H, 4-7H2, 1-3H3 EU number | 230-400-2 NSC number | 73964