Input interpretation
methyl (2e, 6e)-(10r, 11s)-10, 11-epoxy-3, 7, 11-trimethyltrideca-2, 6-dienoate | molar mass
Result
Find the molar mass, M, for methyl (2e, 6e)-(10r, 11s)-10, 11-epoxy-3, 7, 11-trimethyltrideca-2, 6-dienoate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_17H_28O_3 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 17 H (hydrogen) | 28 O (oxygen) | 3 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 17 | 12.011 H (hydrogen) | 28 | 1.008 O (oxygen) | 3 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 17 | 12.011 | 17 × 12.011 = 204.187 H (hydrogen) | 28 | 1.008 | 28 × 1.008 = 28.224 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 M = 204.187 g/mol + 28.224 g/mol + 47.997 g/mol = 280.408 g/mol
Unit conversion
0.28041 kg/mol (kilograms per mole)
Comparisons
≈ 0.39 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4.8 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 4.7×10^-22 grams | 4.7×10^-25 kg (kilograms) | 280 u (unified atomic mass units) | 280 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 280