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H2SO4 + FeCl2 = H2O + HCl + SO2 + Fe2(SO4)3

Input interpretation

H_2SO_4 sulfuric acid + FeCl_2 iron(II) chloride ⟶ H_2O water + HCl hydrogen chloride + SO_2 sulfur dioxide + Fe_2(SO_4)_3·xH_2O iron(III) sulfate hydrate
H_2SO_4 sulfuric acid + FeCl_2 iron(II) chloride ⟶ H_2O water + HCl hydrogen chloride + SO_2 sulfur dioxide + Fe_2(SO_4)_3·xH_2O iron(III) sulfate hydrate

Balanced equation

Balance the chemical equation algebraically: H_2SO_4 + FeCl_2 ⟶ H_2O + HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 FeCl_2 ⟶ c_3 H_2O + c_4 HCl + c_5 SO_2 + c_6 Fe_2(SO_4)_3·xH_2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cl and Fe: H: | 2 c_1 = 2 c_3 + c_4 O: | 4 c_1 = c_3 + 2 c_5 + 12 c_6 S: | c_1 = c_5 + 3 c_6 Cl: | 2 c_2 = c_4 Fe: | c_2 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 2 c_3 = 2 c_4 = 4 c_5 = 1 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 H_2SO_4 + 2 FeCl_2 ⟶ 2 H_2O + 4 HCl + SO_2 + Fe_2(SO_4)_3·xH_2O
Balance the chemical equation algebraically: H_2SO_4 + FeCl_2 ⟶ H_2O + HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 FeCl_2 ⟶ c_3 H_2O + c_4 HCl + c_5 SO_2 + c_6 Fe_2(SO_4)_3·xH_2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cl and Fe: H: | 2 c_1 = 2 c_3 + c_4 O: | 4 c_1 = c_3 + 2 c_5 + 12 c_6 S: | c_1 = c_5 + 3 c_6 Cl: | 2 c_2 = c_4 Fe: | c_2 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 2 c_3 = 2 c_4 = 4 c_5 = 1 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 H_2SO_4 + 2 FeCl_2 ⟶ 2 H_2O + 4 HCl + SO_2 + Fe_2(SO_4)_3·xH_2O

Structures

+ ⟶ + + +
+ ⟶ + + +

Names

sulfuric acid + iron(II) chloride ⟶ water + hydrogen chloride + sulfur dioxide + iron(III) sulfate hydrate
sulfuric acid + iron(II) chloride ⟶ water + hydrogen chloride + sulfur dioxide + iron(III) sulfate hydrate

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 4 H_2SO_4 + 2 FeCl_2 ⟶ 2 H_2O + 4 HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 4 | -4 FeCl_2 | 2 | -2 H_2O | 2 | 2 HCl | 4 | 4 SO_2 | 1 | 1 Fe_2(SO_4)_3·xH_2O | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 4 | -4 | ([H2SO4])^(-4) FeCl_2 | 2 | -2 | ([FeCl2])^(-2) H_2O | 2 | 2 | ([H2O])^2 HCl | 4 | 4 | ([HCl])^4 SO_2 | 1 | 1 | [SO2] Fe_2(SO_4)_3·xH_2O | 1 | 1 | [Fe2(SO4)3·xH2O] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-4) ([FeCl2])^(-2) ([H2O])^2 ([HCl])^4 [SO2] [Fe2(SO4)3·xH2O] = (([H2O])^2 ([HCl])^4 [SO2] [Fe2(SO4)3·xH2O])/(([H2SO4])^4 ([FeCl2])^2)
Construct the equilibrium constant, K, expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 4 H_2SO_4 + 2 FeCl_2 ⟶ 2 H_2O + 4 HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 4 | -4 FeCl_2 | 2 | -2 H_2O | 2 | 2 HCl | 4 | 4 SO_2 | 1 | 1 Fe_2(SO_4)_3·xH_2O | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 4 | -4 | ([H2SO4])^(-4) FeCl_2 | 2 | -2 | ([FeCl2])^(-2) H_2O | 2 | 2 | ([H2O])^2 HCl | 4 | 4 | ([HCl])^4 SO_2 | 1 | 1 | [SO2] Fe_2(SO_4)_3·xH_2O | 1 | 1 | [Fe2(SO4)3·xH2O] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-4) ([FeCl2])^(-2) ([H2O])^2 ([HCl])^4 [SO2] [Fe2(SO4)3·xH2O] = (([H2O])^2 ([HCl])^4 [SO2] [Fe2(SO4)3·xH2O])/(([H2SO4])^4 ([FeCl2])^2)

Rate of reaction

Construct the rate of reaction expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 4 H_2SO_4 + 2 FeCl_2 ⟶ 2 H_2O + 4 HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 4 | -4 FeCl_2 | 2 | -2 H_2O | 2 | 2 HCl | 4 | 4 SO_2 | 1 | 1 Fe_2(SO_4)_3·xH_2O | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 4 | -4 | -1/4 (Δ[H2SO4])/(Δt) FeCl_2 | 2 | -2 | -1/2 (Δ[FeCl2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) HCl | 4 | 4 | 1/4 (Δ[HCl])/(Δt) SO_2 | 1 | 1 | (Δ[SO2])/(Δt) Fe_2(SO_4)_3·xH_2O | 1 | 1 | (Δ[Fe2(SO4)3·xH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/4 (Δ[H2SO4])/(Δt) = -1/2 (Δ[FeCl2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = 1/4 (Δ[HCl])/(Δt) = (Δ[SO2])/(Δt) = (Δ[Fe2(SO4)3·xH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 4 H_2SO_4 + 2 FeCl_2 ⟶ 2 H_2O + 4 HCl + SO_2 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 4 | -4 FeCl_2 | 2 | -2 H_2O | 2 | 2 HCl | 4 | 4 SO_2 | 1 | 1 Fe_2(SO_4)_3·xH_2O | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 4 | -4 | -1/4 (Δ[H2SO4])/(Δt) FeCl_2 | 2 | -2 | -1/2 (Δ[FeCl2])/(Δt) H_2O | 2 | 2 | 1/2 (Δ[H2O])/(Δt) HCl | 4 | 4 | 1/4 (Δ[HCl])/(Δt) SO_2 | 1 | 1 | (Δ[SO2])/(Δt) Fe_2(SO_4)_3·xH_2O | 1 | 1 | (Δ[Fe2(SO4)3·xH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/4 (Δ[H2SO4])/(Δt) = -1/2 (Δ[FeCl2])/(Δt) = 1/2 (Δ[H2O])/(Δt) = 1/4 (Δ[HCl])/(Δt) = (Δ[SO2])/(Δt) = (Δ[Fe2(SO4)3·xH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sulfuric acid | iron(II) chloride | water | hydrogen chloride | sulfur dioxide | iron(III) sulfate hydrate formula | H_2SO_4 | FeCl_2 | H_2O | HCl | SO_2 | Fe_2(SO_4)_3·xH_2O Hill formula | H_2O_4S | Cl_2Fe | H_2O | ClH | O_2S | Fe_2O_12S_3 name | sulfuric acid | iron(II) chloride | water | hydrogen chloride | sulfur dioxide | iron(III) sulfate hydrate IUPAC name | sulfuric acid | dichloroiron | water | hydrogen chloride | sulfur dioxide | diferric trisulfate
| sulfuric acid | iron(II) chloride | water | hydrogen chloride | sulfur dioxide | iron(III) sulfate hydrate formula | H_2SO_4 | FeCl_2 | H_2O | HCl | SO_2 | Fe_2(SO_4)_3·xH_2O Hill formula | H_2O_4S | Cl_2Fe | H_2O | ClH | O_2S | Fe_2O_12S_3 name | sulfuric acid | iron(II) chloride | water | hydrogen chloride | sulfur dioxide | iron(III) sulfate hydrate IUPAC name | sulfuric acid | dichloroiron | water | hydrogen chloride | sulfur dioxide | diferric trisulfate

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