Input interpretation
nitric acid + iron ⟶ water + ferric nitrate + nitrous oxide
Balanced equation
Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and Fe: H: | c_1 = 2 c_3 N: | c_1 = 3 c_4 + 2 c_5 O: | 3 c_1 = c_3 + 9 c_4 + c_5 Fe: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_5 = 1 and solve the system of equations for the remaining coefficients: c_1 = 10 c_2 = 8/3 c_3 = 5 c_4 = 8/3 c_5 = 1 Multiply by the least common denominator, 3, to eliminate fractional coefficients: c_1 = 30 c_2 = 8 c_3 = 15 c_4 = 8 c_5 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 30 + 8 ⟶ 15 + 8 + 3
Structures
+ ⟶ + +
Names
nitric acid + iron ⟶ water + ferric nitrate + nitrous oxide
Chemical names and formulas
| nitric acid | iron | water | ferric nitrate | nitrous oxide Hill formula | HNO_3 | Fe | H_2O | FeN_3O_9 | N_2O name | nitric acid | iron | water | ferric nitrate | nitrous oxide IUPAC name | nitric acid | iron | water | iron(+3) cation trinitrate | nitrous oxide