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HNO3 + ZnCl2 = HCl + Zn(NO3)2

Input interpretation

HNO_3 nitric acid + ZnCl_2 zinc chloride ⟶ HCl hydrogen chloride + Zn(NO3)2
HNO_3 nitric acid + ZnCl_2 zinc chloride ⟶ HCl hydrogen chloride + Zn(NO3)2

Balanced equation

Balance the chemical equation algebraically: HNO_3 + ZnCl_2 ⟶ HCl + Zn(NO3)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 ZnCl_2 ⟶ c_3 HCl + c_4 Zn(NO3)2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Cl and Zn: H: | c_1 = c_3 N: | c_1 = 2 c_4 O: | 3 c_1 = 6 c_4 Cl: | 2 c_2 = c_3 Zn: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 2 HNO_3 + ZnCl_2 ⟶ 2 HCl + Zn(NO3)2
Balance the chemical equation algebraically: HNO_3 + ZnCl_2 ⟶ HCl + Zn(NO3)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HNO_3 + c_2 ZnCl_2 ⟶ c_3 HCl + c_4 Zn(NO3)2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O, Cl and Zn: H: | c_1 = c_3 N: | c_1 = 2 c_4 O: | 3 c_1 = 6 c_4 Cl: | 2 c_2 = c_3 Zn: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 HNO_3 + ZnCl_2 ⟶ 2 HCl + Zn(NO3)2

Structures

 + ⟶ + Zn(NO3)2
+ ⟶ + Zn(NO3)2

Names

nitric acid + zinc chloride ⟶ hydrogen chloride + Zn(NO3)2
nitric acid + zinc chloride ⟶ hydrogen chloride + Zn(NO3)2

Equilibrium constant

Construct the equilibrium constant, K, expression for: HNO_3 + ZnCl_2 ⟶ HCl + Zn(NO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HNO_3 + ZnCl_2 ⟶ 2 HCl + Zn(NO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 ZnCl_2 | 1 | -1 HCl | 2 | 2 Zn(NO3)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HNO_3 | 2 | -2 | ([HNO3])^(-2) ZnCl_2 | 1 | -1 | ([ZnCl2])^(-1) HCl | 2 | 2 | ([HCl])^2 Zn(NO3)2 | 1 | 1 | [Zn(NO3)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([HNO3])^(-2) ([ZnCl2])^(-1) ([HCl])^2 [Zn(NO3)2] = (([HCl])^2 [Zn(NO3)2])/(([HNO3])^2 [ZnCl2])
Construct the equilibrium constant, K, expression for: HNO_3 + ZnCl_2 ⟶ HCl + Zn(NO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 HNO_3 + ZnCl_2 ⟶ 2 HCl + Zn(NO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 ZnCl_2 | 1 | -1 HCl | 2 | 2 Zn(NO3)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HNO_3 | 2 | -2 | ([HNO3])^(-2) ZnCl_2 | 1 | -1 | ([ZnCl2])^(-1) HCl | 2 | 2 | ([HCl])^2 Zn(NO3)2 | 1 | 1 | [Zn(NO3)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HNO3])^(-2) ([ZnCl2])^(-1) ([HCl])^2 [Zn(NO3)2] = (([HCl])^2 [Zn(NO3)2])/(([HNO3])^2 [ZnCl2])

Rate of reaction

Construct the rate of reaction expression for: HNO_3 + ZnCl_2 ⟶ HCl + Zn(NO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HNO_3 + ZnCl_2 ⟶ 2 HCl + Zn(NO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 ZnCl_2 | 1 | -1 HCl | 2 | 2 Zn(NO3)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HNO_3 | 2 | -2 | -1/2 (Δ[HNO3])/(Δt) ZnCl_2 | 1 | -1 | -(Δ[ZnCl2])/(Δt) HCl | 2 | 2 | 1/2 (Δ[HCl])/(Δt) Zn(NO3)2 | 1 | 1 | (Δ[Zn(NO3)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/2 (Δ[HNO3])/(Δt) = -(Δ[ZnCl2])/(Δt) = 1/2 (Δ[HCl])/(Δt) = (Δ[Zn(NO3)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: HNO_3 + ZnCl_2 ⟶ HCl + Zn(NO3)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 HNO_3 + ZnCl_2 ⟶ 2 HCl + Zn(NO3)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HNO_3 | 2 | -2 ZnCl_2 | 1 | -1 HCl | 2 | 2 Zn(NO3)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HNO_3 | 2 | -2 | -1/2 (Δ[HNO3])/(Δt) ZnCl_2 | 1 | -1 | -(Δ[ZnCl2])/(Δt) HCl | 2 | 2 | 1/2 (Δ[HCl])/(Δt) Zn(NO3)2 | 1 | 1 | (Δ[Zn(NO3)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[HNO3])/(Δt) = -(Δ[ZnCl2])/(Δt) = 1/2 (Δ[HCl])/(Δt) = (Δ[Zn(NO3)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | nitric acid | zinc chloride | hydrogen chloride | Zn(NO3)2 formula | HNO_3 | ZnCl_2 | HCl | Zn(NO3)2 Hill formula | HNO_3 | Cl_2Zn | ClH | N2O6Zn name | nitric acid | zinc chloride | hydrogen chloride |  IUPAC name | nitric acid | zinc dichloride | hydrogen chloride |
| nitric acid | zinc chloride | hydrogen chloride | Zn(NO3)2 formula | HNO_3 | ZnCl_2 | HCl | Zn(NO3)2 Hill formula | HNO_3 | Cl_2Zn | ClH | N2O6Zn name | nitric acid | zinc chloride | hydrogen chloride | IUPAC name | nitric acid | zinc dichloride | hydrogen chloride |

Substance properties

 | nitric acid | zinc chloride | hydrogen chloride | Zn(NO3)2 molar mass | 63.012 g/mol | 136.3 g/mol | 36.46 g/mol | 189.4 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) |  melting point | -41.6 °C | 293 °C | -114.17 °C |  boiling point | 83 °C | | -85 °C |  density | 1.5129 g/cm^3 | | 0.00149 g/cm^3 (at 25 °C) |  solubility in water | miscible | soluble | miscible |  dynamic viscosity | 7.6×10^-4 Pa s (at 25 °C) | | |  odor | | odorless | |
| nitric acid | zinc chloride | hydrogen chloride | Zn(NO3)2 molar mass | 63.012 g/mol | 136.3 g/mol | 36.46 g/mol | 189.4 g/mol phase | liquid (at STP) | solid (at STP) | gas (at STP) | melting point | -41.6 °C | 293 °C | -114.17 °C | boiling point | 83 °C | | -85 °C | density | 1.5129 g/cm^3 | | 0.00149 g/cm^3 (at 25 °C) | solubility in water | miscible | soluble | miscible | dynamic viscosity | 7.6×10^-4 Pa s (at 25 °C) | | | odor | | odorless | |

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