HCl + Zn3As2 = ZnCl2 + AsH3

HCl hydrogen chloride + Zn3As2 ⟶ ZnCl_2 zinc chloride + AsH_3 arsine

Balance the chemical equation algebraically: HCl + Zn3As2 ⟶ ZnCl_2 + AsH_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 Zn3As2 ⟶ c_3 ZnCl_2 + c_4 AsH_3 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, Zn and As: Cl: | c_1 = 2 c_3 H: | c_1 = 3 c_4 Zn: | 3 c_2 = c_3 As: | 2 c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 HCl + Zn3As2 ⟶ 3 ZnCl_2 + 2 AsH_3

+ Zn3As2 ⟶ +

hydrogen chloride + Zn3As2 ⟶ zinc chloride + arsine

Construct the equilibrium constant, K, expression for: HCl + Zn3As2 ⟶ ZnCl_2 + AsH_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 HCl + Zn3As2 ⟶ 3 ZnCl_2 + 2 AsH_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HCl | 6 | -6 Zn3As2 | 1 | -1 ZnCl_2 | 3 | 3 AsH_3 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HCl | 6 | -6 | ([HCl])^(-6) Zn3As2 | 1 | -1 | ([Zn3As2])^(-1) ZnCl_2 | 3 | 3 | ([ZnCl2])^3 AsH_3 | 2 | 2 | ([AsH3])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HCl])^(-6) ([Zn3As2])^(-1) ([ZnCl2])^3 ([AsH3])^2 = (([ZnCl2])^3 ([AsH3])^2)/(([HCl])^6 [Zn3As2])

Construct the rate of reaction expression for: HCl + Zn3As2 ⟶ ZnCl_2 + AsH_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 HCl + Zn3As2 ⟶ 3 ZnCl_2 + 2 AsH_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HCl | 6 | -6 Zn3As2 | 1 | -1 ZnCl_2 | 3 | 3 AsH_3 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HCl | 6 | -6 | -1/6 (Δ[HCl])/(Δt) Zn3As2 | 1 | -1 | -(Δ[Zn3As2])/(Δt) ZnCl_2 | 3 | 3 | 1/3 (Δ[ZnCl2])/(Δt) AsH_3 | 2 | 2 | 1/2 (Δ[AsH3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[HCl])/(Δt) = -(Δ[Zn3As2])/(Δt) = 1/3 (Δ[ZnCl2])/(Δt) = 1/2 (Δ[AsH3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| hydrogen chloride | Zn3As2 | zinc chloride | arsine formula | HCl | Zn3As2 | ZnCl_2 | AsH_3 Hill formula | ClH | As2Zn3 | Cl_2Zn | AsH_3 name | hydrogen chloride | | zinc chloride | arsine IUPAC name | hydrogen chloride | | zinc dichloride | arsane

| hydrogen chloride | Zn3As2 | zinc chloride | arsine molar mass | 36.46 g/mol | 346 g/mol | 136.3 g/mol | 77.946 g/mol phase | gas (at STP) | | solid (at STP) | gas (at STP) melting point | -114.17 °C | | 293 °C | -111.2 °C boiling point | -85 °C | | | -62.5 °C density | 0.00149 g/cm^3 (at 25 °C) | | | 0.003186 g/cm^3 (at 25 °C) solubility in water | miscible | | soluble | dynamic viscosity | | | | 1.47×10^-5 Pa s (at 0 °C) odor | | | odorless |