Input interpretation
lutetium fluoride | molar mass
Result
Find the molar mass, M, for lutetium fluoride: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: F_3Lu Use the chemical formula, F_3Lu, to count the number of atoms, N_i, for each element: | N_i F (fluorine) | 3 Lu (lutetium) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) F (fluorine) | 3 | 18.998403163 Lu (lutetium) | 1 | 174.9668 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) F (fluorine) | 3 | 18.998403163 | 3 × 18.998403163 = 56.995209489 Lu (lutetium) | 1 | 174.9668 | 1 × 174.9668 = 174.9668 M = 56.995209489 g/mol + 174.9668 g/mol = 231.9620 g/mol
Unit conversion
0.231962 kg/mol (kilograms per mole)
Comparisons
≈ 0.32 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.2 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.9×10^-22 grams | 3.9×10^-25 kg (kilograms) | 232 u (unified atomic mass units) | 232 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 232