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SnCl2 + Bi(Cl3) = SnCl4 + Bi

Input interpretation

SnCl_2 stannous chloride + BiCl_3 bismuth chloride ⟶ SnCl_4 stannic chloride + Bi bismuth
SnCl_2 stannous chloride + BiCl_3 bismuth chloride ⟶ SnCl_4 stannic chloride + Bi bismuth

Balanced equation

Balance the chemical equation algebraically: SnCl_2 + BiCl_3 ⟶ SnCl_4 + Bi Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SnCl_2 + c_2 BiCl_3 ⟶ c_3 SnCl_4 + c_4 Bi Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Sn and Bi: Cl: | 2 c_1 + 3 c_2 = 4 c_3 Sn: | c_1 = c_3 Bi: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 1 c_3 = 3/2 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 2 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 3 SnCl_2 + 2 BiCl_3 ⟶ 3 SnCl_4 + 2 Bi
Balance the chemical equation algebraically: SnCl_2 + BiCl_3 ⟶ SnCl_4 + Bi Add stoichiometric coefficients, c_i, to the reactants and products: c_1 SnCl_2 + c_2 BiCl_3 ⟶ c_3 SnCl_4 + c_4 Bi Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, Sn and Bi: Cl: | 2 c_1 + 3 c_2 = 4 c_3 Sn: | c_1 = c_3 Bi: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3/2 c_2 = 1 c_3 = 3/2 c_4 = 1 Multiply by the least common denominator, 2, to eliminate fractional coefficients: c_1 = 3 c_2 = 2 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 SnCl_2 + 2 BiCl_3 ⟶ 3 SnCl_4 + 2 Bi

Structures

 + ⟶ +
+ ⟶ +

Names

stannous chloride + bismuth chloride ⟶ stannic chloride + bismuth
stannous chloride + bismuth chloride ⟶ stannic chloride + bismuth

Equilibrium constant

Construct the equilibrium constant, K, expression for: SnCl_2 + BiCl_3 ⟶ SnCl_4 + Bi Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 SnCl_2 + 2 BiCl_3 ⟶ 3 SnCl_4 + 2 Bi Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SnCl_2 | 3 | -3 BiCl_3 | 2 | -2 SnCl_4 | 3 | 3 Bi | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SnCl_2 | 3 | -3 | ([SnCl2])^(-3) BiCl_3 | 2 | -2 | ([BiCl3])^(-2) SnCl_4 | 3 | 3 | ([SnCl4])^3 Bi | 2 | 2 | ([Bi])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([SnCl2])^(-3) ([BiCl3])^(-2) ([SnCl4])^3 ([Bi])^2 = (([SnCl4])^3 ([Bi])^2)/(([SnCl2])^3 ([BiCl3])^2)
Construct the equilibrium constant, K, expression for: SnCl_2 + BiCl_3 ⟶ SnCl_4 + Bi Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 SnCl_2 + 2 BiCl_3 ⟶ 3 SnCl_4 + 2 Bi Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SnCl_2 | 3 | -3 BiCl_3 | 2 | -2 SnCl_4 | 3 | 3 Bi | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression SnCl_2 | 3 | -3 | ([SnCl2])^(-3) BiCl_3 | 2 | -2 | ([BiCl3])^(-2) SnCl_4 | 3 | 3 | ([SnCl4])^3 Bi | 2 | 2 | ([Bi])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([SnCl2])^(-3) ([BiCl3])^(-2) ([SnCl4])^3 ([Bi])^2 = (([SnCl4])^3 ([Bi])^2)/(([SnCl2])^3 ([BiCl3])^2)

Rate of reaction

Construct the rate of reaction expression for: SnCl_2 + BiCl_3 ⟶ SnCl_4 + Bi Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 SnCl_2 + 2 BiCl_3 ⟶ 3 SnCl_4 + 2 Bi Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SnCl_2 | 3 | -3 BiCl_3 | 2 | -2 SnCl_4 | 3 | 3 Bi | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SnCl_2 | 3 | -3 | -1/3 (Δ[SnCl2])/(Δt) BiCl_3 | 2 | -2 | -1/2 (Δ[BiCl3])/(Δt) SnCl_4 | 3 | 3 | 1/3 (Δ[SnCl4])/(Δt) Bi | 2 | 2 | 1/2 (Δ[Bi])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/3 (Δ[SnCl2])/(Δt) = -1/2 (Δ[BiCl3])/(Δt) = 1/3 (Δ[SnCl4])/(Δt) = 1/2 (Δ[Bi])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: SnCl_2 + BiCl_3 ⟶ SnCl_4 + Bi Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 SnCl_2 + 2 BiCl_3 ⟶ 3 SnCl_4 + 2 Bi Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i SnCl_2 | 3 | -3 BiCl_3 | 2 | -2 SnCl_4 | 3 | 3 Bi | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term SnCl_2 | 3 | -3 | -1/3 (Δ[SnCl2])/(Δt) BiCl_3 | 2 | -2 | -1/2 (Δ[BiCl3])/(Δt) SnCl_4 | 3 | 3 | 1/3 (Δ[SnCl4])/(Δt) Bi | 2 | 2 | 1/2 (Δ[Bi])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[SnCl2])/(Δt) = -1/2 (Δ[BiCl3])/(Δt) = 1/3 (Δ[SnCl4])/(Δt) = 1/2 (Δ[Bi])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | stannous chloride | bismuth chloride | stannic chloride | bismuth formula | SnCl_2 | BiCl_3 | SnCl_4 | Bi Hill formula | Cl_2Sn | BiCl_3 | Cl_4Sn | Bi name | stannous chloride | bismuth chloride | stannic chloride | bismuth IUPAC name | dichlorotin | trichlorobismuthane | tetrachlorostannane | bismuth
| stannous chloride | bismuth chloride | stannic chloride | bismuth formula | SnCl_2 | BiCl_3 | SnCl_4 | Bi Hill formula | Cl_2Sn | BiCl_3 | Cl_4Sn | Bi name | stannous chloride | bismuth chloride | stannic chloride | bismuth IUPAC name | dichlorotin | trichlorobismuthane | tetrachlorostannane | bismuth

Substance properties

 | stannous chloride | bismuth chloride | stannic chloride | bismuth molar mass | 189.6 g/mol | 315.3 g/mol | 260.5 g/mol | 208.9804 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 246 °C | 231 °C | -33 °C | 271 °C boiling point | 652 °C | 447 °C | 114 °C | 1560 °C density | 3.354 g/cm^3 | 4.75 g/cm^3 | 2.226 g/cm^3 | 9.8 g/cm^3 solubility in water | | | soluble | insoluble dynamic viscosity | 7 Pa s (at 25 °C) | 41 Pa s (at 25 °C) | 5.8×10^-4 Pa s (at 60 °C) | 1.19×10^-4 Pa s (at 500 °C) odor | odorless | | |
| stannous chloride | bismuth chloride | stannic chloride | bismuth molar mass | 189.6 g/mol | 315.3 g/mol | 260.5 g/mol | 208.9804 g/mol phase | solid (at STP) | solid (at STP) | liquid (at STP) | solid (at STP) melting point | 246 °C | 231 °C | -33 °C | 271 °C boiling point | 652 °C | 447 °C | 114 °C | 1560 °C density | 3.354 g/cm^3 | 4.75 g/cm^3 | 2.226 g/cm^3 | 9.8 g/cm^3 solubility in water | | | soluble | insoluble dynamic viscosity | 7 Pa s (at 25 °C) | 41 Pa s (at 25 °C) | 5.8×10^-4 Pa s (at 60 °C) | 1.19×10^-4 Pa s (at 500 °C) odor | odorless | | |

Units