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Al(OH)3 + Sr(OH)2 = H2O + Sr(AlO2)2

Input interpretation

Al(OH)_3 aluminum hydroxide + Sr(OH)_2 strontium hydroxide ⟶ H_2O water + Sr(AlO2)2
Al(OH)_3 aluminum hydroxide + Sr(OH)_2 strontium hydroxide ⟶ H_2O water + Sr(AlO2)2

Balanced equation

Balance the chemical equation algebraically: Al(OH)_3 + Sr(OH)_2 ⟶ H_2O + Sr(AlO2)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Al(OH)_3 + c_2 Sr(OH)_2 ⟶ c_3 H_2O + c_4 Sr(AlO2)2 Set the number of atoms in the reactants equal to the number of atoms in the products for Al, H, O and Sr: Al: | c_1 = 2 c_4 H: | 3 c_1 + 2 c_2 = 2 c_3 O: | 3 c_1 + 2 c_2 = c_3 + 4 c_4 Sr: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 4 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 Al(OH)_3 + Sr(OH)_2 ⟶ 4 H_2O + Sr(AlO2)2
Balance the chemical equation algebraically: Al(OH)_3 + Sr(OH)_2 ⟶ H_2O + Sr(AlO2)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 Al(OH)_3 + c_2 Sr(OH)_2 ⟶ c_3 H_2O + c_4 Sr(AlO2)2 Set the number of atoms in the reactants equal to the number of atoms in the products for Al, H, O and Sr: Al: | c_1 = 2 c_4 H: | 3 c_1 + 2 c_2 = 2 c_3 O: | 3 c_1 + 2 c_2 = c_3 + 4 c_4 Sr: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 4 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 Al(OH)_3 + Sr(OH)_2 ⟶ 4 H_2O + Sr(AlO2)2

Structures

+ ⟶ + Sr(AlO2)2
+ ⟶ + Sr(AlO2)2

Names

aluminum hydroxide + strontium hydroxide ⟶ water + Sr(AlO2)2
aluminum hydroxide + strontium hydroxide ⟶ water + Sr(AlO2)2

Equilibrium constant

Construct the equilibrium constant, K, expression for: Al(OH)_3 + Sr(OH)_2 ⟶ H_2O + Sr(AlO2)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 Al(OH)_3 + Sr(OH)_2 ⟶ 4 H_2O + Sr(AlO2)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Al(OH)_3 | 2 | -2 Sr(OH)_2 | 1 | -1 H_2O | 4 | 4 Sr(AlO2)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Al(OH)_3 | 2 | -2 | ([Al(OH)3])^(-2) Sr(OH)_2 | 1 | -1 | ([Sr(OH)2])^(-1) H_2O | 4 | 4 | ([H2O])^4 Sr(AlO2)2 | 1 | 1 | [Sr(AlO2)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Al(OH)3])^(-2) ([Sr(OH)2])^(-1) ([H2O])^4 [Sr(AlO2)2] = (([H2O])^4 [Sr(AlO2)2])/(([Al(OH)3])^2 [Sr(OH)2])
Construct the equilibrium constant, K, expression for: Al(OH)_3 + Sr(OH)_2 ⟶ H_2O + Sr(AlO2)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 2 Al(OH)_3 + Sr(OH)_2 ⟶ 4 H_2O + Sr(AlO2)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Al(OH)_3 | 2 | -2 Sr(OH)_2 | 1 | -1 H_2O | 4 | 4 Sr(AlO2)2 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression Al(OH)_3 | 2 | -2 | ([Al(OH)3])^(-2) Sr(OH)_2 | 1 | -1 | ([Sr(OH)2])^(-1) H_2O | 4 | 4 | ([H2O])^4 Sr(AlO2)2 | 1 | 1 | [Sr(AlO2)2] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([Al(OH)3])^(-2) ([Sr(OH)2])^(-1) ([H2O])^4 [Sr(AlO2)2] = (([H2O])^4 [Sr(AlO2)2])/(([Al(OH)3])^2 [Sr(OH)2])

Rate of reaction

Construct the rate of reaction expression for: Al(OH)_3 + Sr(OH)_2 ⟶ H_2O + Sr(AlO2)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 Al(OH)_3 + Sr(OH)_2 ⟶ 4 H_2O + Sr(AlO2)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Al(OH)_3 | 2 | -2 Sr(OH)_2 | 1 | -1 H_2O | 4 | 4 Sr(AlO2)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Al(OH)_3 | 2 | -2 | -1/2 (Δ[Al(OH)3])/(Δt) Sr(OH)_2 | 1 | -1 | -(Δ[Sr(OH)2])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) Sr(AlO2)2 | 1 | 1 | (Δ[Sr(AlO2)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[Al(OH)3])/(Δt) = -(Δ[Sr(OH)2])/(Δt) = 1/4 (Δ[H2O])/(Δt) = (Δ[Sr(AlO2)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: Al(OH)_3 + Sr(OH)_2 ⟶ H_2O + Sr(AlO2)2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 2 Al(OH)_3 + Sr(OH)_2 ⟶ 4 H_2O + Sr(AlO2)2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i Al(OH)_3 | 2 | -2 Sr(OH)_2 | 1 | -1 H_2O | 4 | 4 Sr(AlO2)2 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term Al(OH)_3 | 2 | -2 | -1/2 (Δ[Al(OH)3])/(Δt) Sr(OH)_2 | 1 | -1 | -(Δ[Sr(OH)2])/(Δt) H_2O | 4 | 4 | 1/4 (Δ[H2O])/(Δt) Sr(AlO2)2 | 1 | 1 | (Δ[Sr(AlO2)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/2 (Δ[Al(OH)3])/(Δt) = -(Δ[Sr(OH)2])/(Δt) = 1/4 (Δ[H2O])/(Δt) = (Δ[Sr(AlO2)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| aluminum hydroxide | strontium hydroxide | water | Sr(AlO2)2 formula | Al(OH)_3 | Sr(OH)_2 | H_2O | Sr(AlO2)2 Hill formula | AlH_3O_3 | H_2O_2Sr | H_2O | Al2O4Sr name | aluminum hydroxide | strontium hydroxide | water | IUPAC name | aluminum hydroxide | strontium dihydroxide | water |
| aluminum hydroxide | strontium hydroxide | water | Sr(AlO2)2 formula | Al(OH)_3 | Sr(OH)_2 | H_2O | Sr(AlO2)2 Hill formula | AlH_3O_3 | H_2O_2Sr | H_2O | Al2O4Sr name | aluminum hydroxide | strontium hydroxide | water | IUPAC name | aluminum hydroxide | strontium dihydroxide | water |

Substance properties

| aluminum hydroxide | strontium hydroxide | water | Sr(AlO2)2 molar mass | 78.003 g/mol | 121.6 g/mol | 18.015 g/mol | 205.6 g/mol phase | | | liquid (at STP) | melting point | | | 0 °C | boiling point | | | 99.9839 °C | density | | | 1 g/cm^3 | surface tension | | | 0.0728 N/m | dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |
| aluminum hydroxide | strontium hydroxide | water | Sr(AlO2)2 molar mass | 78.003 g/mol | 121.6 g/mol | 18.015 g/mol | 205.6 g/mol phase | | | liquid (at STP) | melting point | | | 0 °C | boiling point | | | 99.9839 °C | density | | | 1 g/cm^3 | surface tension | | | 0.0728 N/m | dynamic viscosity | | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units

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