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H2O + P2S3 = H2S + H3PO3

Input interpretation

H_2O water + P_2S_3 phosphorus trisulfide ⟶ H_2S hydrogen sulfide + HP(O)(OH)_2 phosphorous acid
H_2O water + P_2S_3 phosphorus trisulfide ⟶ H_2S hydrogen sulfide + HP(O)(OH)_2 phosphorous acid

Balanced equation

Balance the chemical equation algebraically: H_2O + P_2S_3 ⟶ H_2S + HP(O)(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 P_2S_3 ⟶ c_3 H_2S + c_4 HP(O)(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, P and S: H: | 2 c_1 = 2 c_3 + 3 c_4 O: | c_1 = 3 c_4 P: | 2 c_2 = c_4 S: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 H_2O + P_2S_3 ⟶ 3 H_2S + 2 HP(O)(OH)_2
Balance the chemical equation algebraically: H_2O + P_2S_3 ⟶ H_2S + HP(O)(OH)_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2O + c_2 P_2S_3 ⟶ c_3 H_2S + c_4 HP(O)(OH)_2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, P and S: H: | 2 c_1 = 2 c_3 + 3 c_4 O: | c_1 = 3 c_4 P: | 2 c_2 = c_4 S: | 3 c_2 = c_3 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 1 c_3 = 3 c_4 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 H_2O + P_2S_3 ⟶ 3 H_2S + 2 HP(O)(OH)_2

Structures

+ ⟶ +
+ ⟶ +

Names

water + phosphorus trisulfide ⟶ hydrogen sulfide + phosphorous acid
water + phosphorus trisulfide ⟶ hydrogen sulfide + phosphorous acid

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2O + P_2S_3 ⟶ H_2S + HP(O)(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 H_2O + P_2S_3 ⟶ 3 H_2S + 2 HP(O)(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 6 | -6 P_2S_3 | 1 | -1 H_2S | 3 | 3 HP(O)(OH)_2 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 6 | -6 | ([H2O])^(-6) P_2S_3 | 1 | -1 | ([P2S3])^(-1) H_2S | 3 | 3 | ([H2S])^3 HP(O)(OH)_2 | 2 | 2 | ([HP(O)(OH)2])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-6) ([P2S3])^(-1) ([H2S])^3 ([HP(O)(OH)2])^2 = (([H2S])^3 ([HP(O)(OH)2])^2)/(([H2O])^6 [P2S3])
Construct the equilibrium constant, K, expression for: H_2O + P_2S_3 ⟶ H_2S + HP(O)(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 H_2O + P_2S_3 ⟶ 3 H_2S + 2 HP(O)(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 6 | -6 P_2S_3 | 1 | -1 H_2S | 3 | 3 HP(O)(OH)_2 | 2 | 2 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2O | 6 | -6 | ([H2O])^(-6) P_2S_3 | 1 | -1 | ([P2S3])^(-1) H_2S | 3 | 3 | ([H2S])^3 HP(O)(OH)_2 | 2 | 2 | ([HP(O)(OH)2])^2 The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2O])^(-6) ([P2S3])^(-1) ([H2S])^3 ([HP(O)(OH)2])^2 = (([H2S])^3 ([HP(O)(OH)2])^2)/(([H2O])^6 [P2S3])

Rate of reaction

Construct the rate of reaction expression for: H_2O + P_2S_3 ⟶ H_2S + HP(O)(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 H_2O + P_2S_3 ⟶ 3 H_2S + 2 HP(O)(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 6 | -6 P_2S_3 | 1 | -1 H_2S | 3 | 3 HP(O)(OH)_2 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 6 | -6 | -1/6 (Δ[H2O])/(Δt) P_2S_3 | 1 | -1 | -(Δ[P2S3])/(Δt) H_2S | 3 | 3 | 1/3 (Δ[H2S])/(Δt) HP(O)(OH)_2 | 2 | 2 | 1/2 (Δ[HP(O)(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[H2O])/(Δt) = -(Δ[P2S3])/(Δt) = 1/3 (Δ[H2S])/(Δt) = 1/2 (Δ[HP(O)(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2O + P_2S_3 ⟶ H_2S + HP(O)(OH)_2 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 H_2O + P_2S_3 ⟶ 3 H_2S + 2 HP(O)(OH)_2 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2O | 6 | -6 P_2S_3 | 1 | -1 H_2S | 3 | 3 HP(O)(OH)_2 | 2 | 2 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2O | 6 | -6 | -1/6 (Δ[H2O])/(Δt) P_2S_3 | 1 | -1 | -(Δ[P2S3])/(Δt) H_2S | 3 | 3 | 1/3 (Δ[H2S])/(Δt) HP(O)(OH)_2 | 2 | 2 | 1/2 (Δ[HP(O)(OH)2])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[H2O])/(Δt) = -(Δ[P2S3])/(Δt) = 1/3 (Δ[H2S])/(Δt) = 1/2 (Δ[HP(O)(OH)2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| water | phosphorus trisulfide | hydrogen sulfide | phosphorous acid formula | H_2O | P_2S_3 | H_2S | HP(O)(OH)_2 Hill formula | H_2O | P_2S_3 | H_2S | H_3O_3P name | water | phosphorus trisulfide | hydrogen sulfide | phosphorous acid
| water | phosphorus trisulfide | hydrogen sulfide | phosphorous acid formula | H_2O | P_2S_3 | H_2S | HP(O)(OH)_2 Hill formula | H_2O | P_2S_3 | H_2S | H_3O_3P name | water | phosphorus trisulfide | hydrogen sulfide | phosphorous acid

Substance properties

| water | phosphorus trisulfide | hydrogen sulfide | phosphorous acid molar mass | 18.015 g/mol | 158.1 g/mol | 34.08 g/mol | 81.995 g/mol phase | liquid (at STP) | | gas (at STP) | solid (at STP) melting point | 0 °C | | -85 °C | 74 °C boiling point | 99.9839 °C | | -60 °C | density | 1 g/cm^3 | | 0.001393 g/cm^3 (at 25 °C) | 1.597 g/cm^3 surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 1.239×10^-5 Pa s (at 25 °C) | odor | odorless | | |
| water | phosphorus trisulfide | hydrogen sulfide | phosphorous acid molar mass | 18.015 g/mol | 158.1 g/mol | 34.08 g/mol | 81.995 g/mol phase | liquid (at STP) | | gas (at STP) | solid (at STP) melting point | 0 °C | | -85 °C | 74 °C boiling point | 99.9839 °C | | -60 °C | density | 1 g/cm^3 | | 0.001393 g/cm^3 (at 25 °C) | 1.597 g/cm^3 surface tension | 0.0728 N/m | | | dynamic viscosity | 8.9×10^-4 Pa s (at 25 °C) | | 1.239×10^-5 Pa s (at 25 °C) | odor | odorless | | |

Units

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